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Llana [10]
3 years ago
13

10x^2+29x-21/6x^2+19x-7

Mathematics
1 answer:
Anastaziya [24]3 years ago
5 0
The answer is 13x^2 + 96x - 14 / 2
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Which of the following options have the same value as
Keith_Richards [23]

Question:

Which of the following options have the same value as 65% of 20?

Choose 2 answers:

(A) 0.65⋅20

(B) 65/100 divided by 20

(C) 65/20 * 100

(D) 65 * 20

Answer:

Option A has the same value as  65% of 20

Step-by-step explanation:

Let x be the value of  65% of 20

x = 65\% of 20

x = \frac{65}{100} \times 20

x =0.65 \times 20

x =13

Thus 65% of 20 is 13

Now ,

<u>Solving Option A</u>

=> (0.65) \cdot (20)

=> 13

<u>Solving Option B</u>

=> 65/100 divided by 20

=>\frac{\frac{65}{100}}{20}

=>\frac{0.65}{20}

=>0.0325

<u>Solving Option C</u>

=>65/20 * 100

=>\frac{65}{20} \times 100

=>3.25 \times 100

=>325

<u>Solving Option D</u>

=> 65 * 20

=>65 \times 20

=> 1300

8 0
3 years ago
Read 2 more answers
Joe earns $14 an hour and Blaine earns $18 per hour. Joe receives a raise of $1.75 every six months, and Blaine receives a raise
Katarina [22]

After 4 interval of six months, Joe to earn same hourly rate as Blaine

<em><u>Solution:</u></em>

Given that,

Amount earned by Joe = $ 14 per hour

Amount earned by Blaine = $ 18 per hour

Lets assume the number of six month intervals be "x"

<em><u>Joe receives a raise of $1.75 every six months</u></em>

Therefore,

Joe earning: 14 + 1.75(number of six month intervals)

Equation for Joe earning: 14 + 1.75x ------- eqn 1

<em><u>Blaine receives a raise of $0.75 every six months</u></em>

Therefore,

Blaine earning: 18 + 0.75(number of six month intervals)

Equation for Blaine earning: 18 + 0.75x ------------ eqn 2

The number of six-month intervals it will take Joe to earn the same hourly rate as Blaine,

Eqn 1 must be equal to eqn 2

14+1.75x = 18+0.75x\\\\1.75x-0.75x = 18-14\\\\1x = 4\\\\x = 4

Thus after 4 interval of six months, Joe to earn same hourly rate as Blaine.

8 0
3 years ago
Both answers plssss ?????!?
Troyanec [42]

Answer:

4) C

5) C

Step-by-step explanation:

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