When would there be only for different equations for a set of math mountain numbers

In a mathematics class, the following test scores were recorded for a student. Find the mode 90, 99, 95, 78, 81, 89

tatyana61 [14]

Answer:

78,81,89,90,95,99

Step-by-step explanation:

there is no mode because none of the numbers repeat themselves

8 0

2 years ago

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what differences can be found when contrasting the mood of third person acc with that of claudettes first person account?

Solnce55 [7]

Answer: The mood of the third-person account is less emotional and more matter-of-fact. The mood of Claudette's account is less emotional and more matter-of-fact.

Step-by-step explanation:

6 0

2 years ago

A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.

Anastaziya [24]

Answer:

C) 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins

Step-by-step explanation:

Your goal is to find out how many of each item will equate to 21 dollars. Your function is as follows:

1.5x+3y+1.5z=21

Where x, y, z are peanuts, almonds, raisins respectively (in that order). 21 is the total cost of the mixture.

All you have to do is start plugging in the variables given in the answer choices.

A) Peanuts (x) = 3, Almonds (y) = 6, Raisins (z) = 2

Everywhere you see x,y,z, you replace with their value.

$1.5x+3y+1.5z=21\\1.5(3)+3(6)+1.5(2)=21\\4.5+12+3=21\\\\19.5 \neq 21$

A doesn't equal 21. On to the next one.

B) Peanuts (x) = 8, Almonds (y) = 6, Raisins (z) = 2

Everywhere you see x,y,z, you replace with their value.

$1.5x+3y+1.5z=21\\1.5(8)+3(1)+1.5(2)=21\\12+3+3=21\\\\18 \neq 21$

B also doesn't equal 21. On to the next one...

C) Peanuts (x) = 6, Almonds (y) = 3, Raisins (z) = 2

Everywhere you see x,y,z you replace with their value.

$1.5x+3y+1.5z=21\\1.5(6)+3(3)+1.5(2)=21\\9+9+3=21\\\\\\21 = 21$

Both sides of the equation equal 21 which means C is our answer.

7 0

2 years ago

The triangle described is of the form SSA. Determine if there is no triangle possible, one triangle possible, or two triangles p

kvv77 [185]

Answer: The way to work this problem is to sketch the SSA-described triangle.

Horizontally, mark a ray stemming from point C, going to the right.

From point C, at an angle of elevation of 20 degrees, draw a segment a = 6.3, ending at point B.

Now, from point B, draw a segment perpendicular to the horizontal ray and label it h, for altitude.

Calculate h = 6.3 sin 20o = 2.1547.

Now imagine that, dangling from point B, you have a segment of length c = 9.3; in fact, put a compass with steel point at B and radius 9.3, and draw a big arc. you'll see that it can intersect the horizontal ray only once; in its swing toward point C, due to c > a, there will be no second intersection of the ray (the arc 'overshoots' the ray).

Thus you see that only one solution exists, and the Law of Sines can be used to solve the triangle:

sin 20 / 9.3 = sin A / 6.3 and this leads to A = 13.4 degrees...and B = 180 - 20 - 13.4 = 146o.

I'll let you solve for b (side AC).

6 0

2 years ago

h(x)= \dfrac{1}{8} x^3 - x^2h(x)= 8 1 x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided b

Nesterboy [21]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given the function $h(x)=\dfrac{1}{8}x^3-x^2$

The average rate of change of the function h(x) over the interval $a\le x\le b$ can be calculated using formula

$\dfrac{h(b)-h(a)}{b-a}$

In your case,

$a=-2,\\ \\b=2,$

so the average rate of change is

$\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}$

6 0

2 years ago