When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
Answer:
that's easy decide which one is more reasonable to your question
Step-by-step explanation:
2:15 -40 2:16 -40 2:17 -40 2:18 -40 THE ANSWER IS -40
So, for the area of a circle, there should be a line in the middle. Correct?
Well, that line is the diameter. Then cut that in half, so if the diameter is 6, the radius is 3.
Then multiply the the radius by the radius, so 3x3 once you get that, multiply the answer by pi. Pi= 3.14, so if you do 3x3x3.14 you should get 28.26. Hope this helps.
Answer:74.55 beat per minute
Step-by-step explanation:
Given
Heart beat is 52 beat per minute
i.e. 
beat per sec
If heart rate is increases 1.25 % each sec
suppose B is the heart beat at first second therefore heat beat at 2 nd second
For 3 rd sec
similarly for 3 sec
