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4 years ago

How do you no when a number line shows a point at 5/6

Mathematics

1 answer:

shutvik [7]4 years ago

8 0

It just like counting by one count the line like 1/6,2/6 ,3/6,4/6 I think you get is

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Thank you so much!!!

vova2212 [387]

Answer:

$\fbox{\begin{minipage}{16em}Option D: y = (4/7)x + 8 is correct\end{minipage}}$

Step-by-step explanation:

(1) A typical form of equation of a line is:

$y = Mx + b$

with, $M$ is slope and $b$ is y-intercept.

(2) Another straight line has equation in form of:

$y = Nx + c$

with $N$ is slope and $c$ is y-intercept

(3) If these two lines are perpendicular, according to the property of two perpendicular lines on the two-dimensional plane, we have:

$M$ x $N$ = -1

(4) Transform the given equation of original line into typical form:

$7x + 4y = -24\\$

<=> $4y = -7x - 24$

<=> $y = (\frac{-7}{4})x - \frac{24}{4}$

<=> $y = (\frac{-7}{4})x - 6$

=> $M = \frac{-7}{4}$

=> $N = \frac{-1}{M} = \frac{-1}{\frac{-7}{4} } = \frac{-4}{-7} = \frac{4}{7}$

=> Option D: $y = (\frac{4}{7})x + 8$ is correct (Slope = $\frac{4}{7}$ )

Hope this helps!

4 0

3 years ago

can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylind

shutvik [7]

the new radius be to meet the client's need is 4.9 cm .

Step-by-step explanation:

Here we have , can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylindrical can that has the same volume but is 15 cm tall. We need to find What must the new radius be to meet the client's need . Let's find out:

Let we have two cylinders of volume $V_1 , V_2$ with parameters as follows :

$r_1=6cm\\h_1=10cm\\r_2=?\\h_2=15cm$

We know that volume of cylinder is $\pi r^2h$ , According to question volume of both cylinder is equal i.e

⇒ $V_1=V_2$

⇒ $\pi (r_1)^2h_1= \pi (r_2)^2h_2$

⇒ $(r_1)^2h_1= (r_2)^2h_2$

⇒ $\frac{(r_1)^2h_1}{h_2}= (r_2)^2$

⇒ $(r_2) =\sqrt{ \frac{(r_1)^2h_1}{h_2}}$ Putting all values

⇒ $(r_2) =\sqrt{ \frac{(6)^2(10)}{15}}$

⇒ $(r_2) =\sqrt{ \frac{36(10)}{15}}$

⇒ $(r_2) =\sqrt{ \frac{360}{15}}$

⇒ $(r_2) =\sqrt{24}$

⇒ $(r_2) =4.9cm$

Therefore , the new radius be to meet the client's need is 4.9 cm .

7 0

3 years ago

Read 2 more answers

What is 2x+3=r+2 ???

tankabanditka [31]

Answer:

R.4

thank you good luck

6 0

3 years ago

Read 2 more answers

A rectangle has an area of 20 ft.² in a similar rectangle has an area of 180 ft.² what is the ratio of areas of the similar

vovikov84 [41]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{cccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------\\\\$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s^2}{s^2}=\cfrac{20}{180}\implies \left( \cfrac{s}{s} \right)^2=\cfrac{20}{180}\implies \cfrac{s}{s}=\sqrt{\cfrac{20}{180}}
\\\\\\
\cfrac{s}{s}=\cfrac{\sqrt{20}}{\sqrt{180}}\implies \cfrac{s}{s}=\cfrac{2\sqrt{5}}{6\sqrt{5}}\implies \cfrac{s}{s}=\cfrac{2}{6}\implies \cfrac{s}{s}=\cfrac{1}{3}$

6 0

4 years ago

I need help!!!! Evaluate 4/7 + 8/3 in fraction form

Reptile [31]

Answer:

3 5/21.
68/21

Step-by-step explanation:

Given equation:

4/7 + 8/3

Solve:

4/7 + 8/3
= 12/21 + 56/21
= $\frac{12 + 56}{21 + 0}$
= 3 5/21.
= 68/21.

8 0

2 years ago