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3 years ago

What is the distance between (1,4) and (4,0) ?

Mathematics

1 answer:

marishachu [46]3 years ago

5 0

Answer:

5 units

Step-by-step explanation:

To calculate the distance (d) use the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (1, 4) and (x₂, y₂ ) = (4, 0)

d = $\sqrt{(4-1)^2+(0-4)^2}$

= $\sqrt{3^2+(-4)^2}$

= $\sqrt{9+16}$ = $\sqrt{25}$ = 5

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The figure shows the construction steps to bisect an angle. The steps are in an incorrect order. What is the correct order of th

klemol [59]

Answer:

The correct order of the steps is CEABD ⇒ B

Step-by-step explanation:

Let us arrange the figures

To construct a bisector of an angle

First: Draw angle AOB

First step is figure C

Second: Place the pin of the compass on point O and draw an arc intersects the two sides of the angle OA and OB at points D and E

Second step is figure E

Third: Place the compass on point D and draw an arc in the interior of the angle

Third step is figure A

Fourth: without change the open of the compass place its pin on point E and draw an arc which intersects the arc drawn from point D at point C

Fourth step is figure B

Fifth: Draw a line from point A to point C, this line AC is the bisector of angle AOB

Fifth step is figure D

The correct order of the steps is CEABD

6 0

3 years ago

What is the factored form of 6n4 – 24n3 + 18n?

seropon [69]

Answer: Its factored form will be

$6n(n-1)(n^2-3n-3)$

Step-by-step explanation:

Since we have given that

$6n^4-24n^3+18n$

So, we need to factor ,

$6n(n^3-4n^2+3)$

Now,

$\text{Let }p(n)=n^3-4n^2+3$

Now, by hit and trial method, we put n=1,

$p(1)=1^3-4\times1^2+3=1-4+3=1-1=0$

$n=1\\n-1=0$

So, n-1 is also factor of p(n).

Now,

$\frac{n^3-4n^2+3}{n-1}=n^2-3n-3$

So, its factored form will be

$6n(n-1)(n^2-3n-3)$

8 0

3 years ago

Read 2 more answers

Can someone help me plz

enyata [817]

Answer:the answer is 420 :)

Step-by-step explanation:

5 0

3 years ago

1,8,27,64... What are the three next numbers in the pattern. PLEASE ANSWER FAST!

Sav [38]

Answer:

125, 216, 343,

Step-by-step explanation:

7 0

3 years ago

Comparing Leaking Pool Problem

Blababa [14]

Answer:

Pool 1 leaks faster than pool 2.

Step-by-step explanation:

Rates of change

The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.

We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.

To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:

15 minutes = 15/60 = 1/4 hours

20 minutes = 20/60 = 1/3 hours

Now compute both rates of change:

Pool 1:

$\displaystyle ROC_1=\frac{2/3}{1/4}=\frac{8}{3}\approx 2.67\ gal/h$

Pool 2:

$\displaystyle ROC_2=\frac{3/4}{1/3}=\frac{9}{4}= 2.25\ gal/h$

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.

8 0

3 years ago