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3 years ago

~Extra ~ question ~ for ~ the ~ weebs ~ at ~ the ~ end.~

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

6 0

Answer:

Imma be truthful here

Hotest boy: Bakugo

Cutest boy: Deku (everyone can relate) and Mineta

Toughest boy: Todoroki (hes mentally still stable after all that trauma-)

Craziest boy: Shigakari

Most Annoying Boy: Twice

Now imma talk about the mineta thing

Mineta would be the perfect little guy in the series if he wasnt a perv. He's super smart, but lets his single pringle self get in the way. So really he is cute when hes not being a perv.

meriva3 years ago

4 0

Answer:

hello~ is this how im sopoused to talk~

Step-by-step explanation:

good bye~

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Answer:

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3 years ago

Read 2 more answers

A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

The 95% confidence interval is $0.0503 < p < 0.1297$

The sample proportion is $\r p = 0.09$

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

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Answer:

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Step-by-step explanation:

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