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Alex777 [14]
3 years ago
9

I need help with this question asap

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0
((2t+10) / 2) + ((3t-15) / 2) + (3s) = 180 
((2t+10) / 2) + ((3t-15) / 2) + (4r) = 180
((2t+10) / 2) + ((3t-15) / 2) + (3s) = ((2t+10) / 2) + ((3t-15) / 2) + (4r) 
(2t+10) = (3t-15)   t=25
2*25+10= 60  ,   3*25-15=60
60+60= 120 ,   This rectangle has a total of 360 degrees 
360 - 120 = 240
240/2 =120
120/ 4 = 30  ,  120/3 = 40
r=30    s=40

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((6x-8)-2x)-((12x-7)-(4x-5))
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Answer:

-12x + 4

Step-by-step explanation:

(6x - 8 - 2x) - (12x - 7) - (4x - 5)

The subtraction sign before the parenthesis is basically multiplying by -1, so the subtraction signs in the parenthesis have to change to addition. After that, you can remove the parenthesis.

6x - 8 - 2x - 12x + 7 - 4x + 5

Simplified = -12x + 4

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kirill [66]

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2 years ago
What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint
leonid [27]

The right answer is c. –2.24, 2, 2.24


This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.


1. Using a graphing calculator.


We have the following polynomial equation:

x^3-5x+5=2x^2-5


By ordering this equation we have:

x^3-2x^2-5x+10=0


So, we can say that this equation comes from a function given by:

f(x)=x^3-2x^2-5x+10


Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of f(x) which are:


x_{1}=-2.236 \\ \\ x_{2}=2 \\ \\ x_{3}=2.236


Finally, rounding noninteger roots to the nearest hundredth we have:


\boxed{Root_{1}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=2.24}


2. Using a system of equations.


The ordered equation is:

x^3-2x^2-5x+10=0


By arranging to factor out we have:

x^3-5x-2x^2+10=0


Then, by factoring:

x(x^2-5)-2(x^2-5)=0


Term (x^2-5) is a common factor, thus:


(x-2)(x^2-5)=0 \\ \\ (x-2)(x-\sqrt{5})(x+\sqrt{5})=0 \\ \\ Finally: \\ \\ \boxed{Root_{1}=-\sqrt{5}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=\sqrt{5}=2.24}

6 0
3 years ago
Read 2 more answers
4(3d-2x)-(2d-5x)<br> Maths help plz.....
nata0808 [166]

Answer:

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Step-by-step explanation:

Distribute the 4: 12d - 8x

Distribute the -1: -2d + 5x

Add like terms: 10d - 3x

6 0
3 years ago
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