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Juli2301 [7.4K]
3 years ago
11

PLSSSS HELP ASAPPPP Which is the graph of g(x) = [X +3]

Mathematics
2 answers:
adelina 88 [10]3 years ago
6 0

Answer:

the last  one

Step-by-step explanation:

the image of [0.1] is 1 using X and now it's X+3

so the image will be 4

zubka84 [21]3 years ago
5 0

Answer:

Last graph, 4, D

Step-by-step explanation:

g(x) = [X +3] is the graph we're looking for

g(x) = X would be a straight line with an equation of y=1x+0 and a slope of 1

So

g(x) = [X +3] would be adding 3 to the vertical asymptote of g(x)

or it would look like

y=1x+3

so the answer to this would be the line that has y = x+3

So the last one

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The equation p(t) = 1.e represents a
zvonat [6]

Answer:

(b), (d) and (e)

Step-by-step explanation:

Given

p(t) = 1 * e^t

See attachment for y = p(t)

Required

Select true statements from the given options

(a) \ln(30) = days the bacteria reaches 30000

We have:

p(t) = 1 * e^t

In this case:

t = \ln(30) and p(t) = 30000

So, we have:

30000 = 1 * e^{\ln(30)}

30000 = e^{\ln(30)}

Using a calculator, we have:

e^{\ln(30)} = 30

So:

30000 = 30

The above equation is false.

(a) is not true

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We have:

p(t) = 1 * e^t

Let t = 3

So;

p(3) = 1 * e^3

From the graph, p(3) = 20

So:

20 = 1 * e^3

20 = e^3

Take natural logarithm of both sides

\ln(20) = \ln(e^3)

This gives:

\ln(20) = 3

(b) is true

(c) \ln(t) = y is the logarithm form of y = e^t

We have:

y = e^t

Take natural logarithm of both sides

\ln(y) = \ln(e^t)

This gives:

\ln(y) = t

\ln(y) = t  \ne \ln(t) = y

(c) is false

(d) e^4 > 50 and  \ln(50) < 4

From the graph, we have:

e^4 = 54 --- rough readings

This implies that:

e^4 > 50 is true

Because 54 > 50

Take natural logarithm of both sides

\ln(54) > \ln(50)

Rewrite as:

\ln(50) < \ln(54)

We have:

e^4 = 54

Take natural logarithm of both sides

\ln(e^4) = \ln(54)

4 = \ln(54)

\ln(54) = 4

Substitute \ln(54) = 4 in \ln(50) < \ln(54)

\ln(50) < 4

(d) is true

(e) The graph shows that 10 \approx \ln(2.3)

We have:

p(t) = 1 * e^t

Let t = 2.3

So;

p(2.3) = 1 * e^{2.3}

From the graph,

p(2.3) = 10 ---- rough readings

So:

10 = 1 * e^{2.3}

10 = e^{2.3}

Take natural logarithm of both sides

\ln(10) = \ln(e^{2.3})

This gives:

\ln(10) = 2.3

(e) is true

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