Answer:
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Step-by-step explanation:
The height h of the ball is modeled by the following equation
The problem want you to find the times the ball will be 48 feet above the ground.
It is going to be when:
We can simplify by 16t. So
It means that
16t = 0
t = 0
or
t - 2 = 0
t = 2
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
end behavior is affect by the exponent and whether its negative or positive
y = y^3 starts negative from -∞ to 0 the from 0 to +∞ goes positive
since this equation is negative its switched
-∞ to 0 its positive x>0
0 to +∞ is negative x<0
Depending on how big the center is, I would say 15.
I hope this helped!
20×1=20
20×2=40
20×3=60
20×4=80
20×5=100
20×6=120
20×7=140
20×8=160
20×9=180
20×10=200
(Only include this if the table is up to 12)
20×11=220
20×12=240
