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Novay_Z [31]
3 years ago
15

Jarin wants to save enough money

Mathematics
2 answers:
barxatty [35]3 years ago
7 0

Answer: 12 weeks

Step-by-step explanation:

you do 2200 minus 550 then with the answer you divide it by 20 then 7 and then get an estimate of 12. Hope this helps!

Bezzdna [24]3 years ago
4 0

Answer:

12 weeks

Step-by-step explanation:

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Four times a number w minus 3.5 is less than or equal to -1.5​
DIA [1.3K]

Answer:

This is your answer ☺️☺️

6 0
3 years ago
3/4 + (1/3 ÷ 1/6) - (-1/2) =
Aleonysh [2.5K]
The answer is 13/14
4 0
4 years ago
Approximately how many times greater is 1.2×103 than 4×10−1 ?
Galina-37 [17]
3000 Quick answer
Let your calculator do the work. Be careful how you enter this in. (Are you supposed to estimate it? We'll get around to that.) Write it like this.

1.2 * 10^3 divided by 4 * 10^-1 Your calculator will do this nicely. The trick is the - 1. Put it in the calculator like this.
1.2 
*
10
^
3
=
÷
4
*
10
^
(-1) 
= The calculator should read 3000
That's one way to do it. Another way is just to do it all by hand. The numbers are easy enough
1.2 * 10^3 means shift the decimal 3 places right. 1 200 which is 1200
4 * 10^-1 can be handled 2 ways 10 to the minus 1 in the denominator becomes 10^1 in the numerator. Notice the sign change on the 10 when you shift if :it becomes plus! That's why you did it.

1200 * 10^1 
12000

Now you are still left with 4 in the denominator.
12000/4 = 3000. 

The first method always works. The second one gives you a better understanding of how powers work. There are other ways of doing this, but these are the two best, I think.
4 0
3 years ago
Yuri thinks that 3/4 is a root of the following function.
sineoko [7]

Given:

The polynomial function is

q(x)=6x^3+19x^2-15x-28

Yuri thinks that \dfrac{3}{4} is a root of the given function.

To find:

Why \dfrac{3}{4} cannot be a root?

Solution:

We have,

q(x)=6x^3+19x^2-15x-28

If \dfrac{3}{4} is a root, then the value of the function at \dfrac{3}{4} is 0.

Putting x=\dfrac{3}{4} in the given function, we get

q(\dfrac{3}{4})=6(\dfrac{3}{4})^3+19(\dfrac{3}{4})^2-15(\dfrac{3}{4})-28

q(\dfrac{3}{4})=6(\dfrac{27}{64})+19(\dfrac{9}{16})-\dfrac{45}{4}-28

q(\dfrac{3}{4})=3(\dfrac{27}{32})+\dfrac{171}{16}-\dfrac{45}{4}-28

q(\dfrac{3}{4})=\dfrac{81}{32}+\dfrac{171}{16}-\dfrac{45}{4}-28

Taking LCM, we get

q(\dfrac{3}{4})=\dfrac{81+342-360-896}{32}

q(\dfrac{3}{4})=\dfrac{-833}{32}\neq 0

Since the value of the function at \dfrac{3}{4} is not equal to 0, therefore, \dfrac{3}{4} is not a root of the given function.

4 0
3 years ago
What is 0.34 in word form?
Rainbow [258]
The answer is thirtyfour.
6 0
3 years ago
Read 2 more answers
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