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WARRIOR [948]
2 years ago
8

Find the indicated values, where

Mathematics
2 answers:
nataly862011 [7]2 years ago
4 0

For this case we have, that given two functions f (x) and g (x), then:

The composite function of f with g is: (gof) (x) = g [f (x)]

The function composed of g with f is: (fog) (x) = f [g (x)]

In this case we have:

f (x) = 1 + x\\g (t) = t ^ 2-1

First we solve g (1):

g (1) = 1 ^ 2-1 = 0

Now:

2 * g (1) = 2 * 0 = 0

Then we have left:

f (0) = 1 + 0 = 1

So, we have to:

f (2g (1)) = 1

Answer:

Option A

jonny [76]2 years ago
3 0

A.

Firstly, you should deal with the inner function.

1^2 - 1 = 0

And

2 x 0 = 0

So 2g(1) = 0

Applying the outer function:

0 + 1 = 1

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Find the volume of this prism 41cm2 11cm
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Answer:

451 cm^3

Step-by-step explanation:

V = Bh (base area and height multiplied)

41 cm^2 x 11 cm = 451 cm^3

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3 years ago
What is the median of 5, 2, 9, 21, 12, 3
finlep [7]

2, 3,5,12,21

it is 5

this is the answer

7 0
3 years ago
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Jacob distributed a survey to his fellow students asking them how many hours they'd spent playing sports in the past day. He als
andrew-mc [135]

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2 years ago
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What is the 8th term of the geometric sequence a2 = 20 and r = 5
algol [13]

Answer:

8th term of geometric sequence is 312500

Step-by-step explanation:

 Given :  a_2=20 and common ratio (r) = 5

We have to find the 8th term of the geometric sequence whose a_2=20 and common ratio (r) = 5  

Geometric sequence is a sequence of numbers in which next term is found by multiplying by a constant called the common ratio (r).

     a_n=ar^{n-1}  ......(1)

where  a_n  is nth term and a is first term.

For given sequence

a can be find using  a_2=20 and r =  5

Substitute in (1) , we get,

a_2=ar^{2-1}

\Rightarrow 20=a(5)  

\Rightarrow a=4

Thus, 8th term of the sequence denoted as  a_8

Substitute n= 8 in (1) ,  we get,

a_8=ar^{8-1} \\\\a_8=(4)r_{7} \\\\a_8=4(5)^7=4 \times 78125=312500

Thus 8th term of geometric sequence is 312500

8 0
3 years ago
If a pool deck of 650 square feet is to be laid with concrete 3" thick, what volume of concrete will have to be poured in cubic
AVprozaik [17]

Volume is a three-dimensional scalar quantity. The volume of concrete that will have to be poured into the pool deck is 6.0185 cubic yards.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Since an inch is equal to 1/12 of a foot. Therefore, the thickness of the pool deck is,

3 inches = 0.25 foot

If a pool deck of 650 square feet is to be laid with concrete 3" thick, then the volume of concrete that will be needed is,

Volume of concrete = 650 ft² × 0.25 ft = 162.5 ft³

Now, one yard is equal to 3 feet, therefore,

1 cubic foot = 1/27 cubic yards

162.5 cubic feet = 6.0185 cubic yards

Hence, the volume of concrete that will have to be poured into the pool deck is 6.0185 cubic yards.

Learn more about Volume:

brainly.com/question/13338592

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6 0
1 year ago
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