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e-lub [12.9K]
4 years ago
6

El Bowen borrowed $10,000 for 3 years 13.75% rate of interest. Find the simple interest.

Mathematics
1 answer:
aniked [119]4 years ago
5 0

Answer:$4125

Step-by-step explanation:

Using the I = P x R x T formula, we can find the simple interest. Substitute all the values into this equation and you get : I = 10,000 x 13.75 x 3. Once you multiply all the values, $4125 is the answer you get. :)

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two lines intersect.One has gradient 4 and y-axis intercept 3. The other has gradient 6 and cuts the y-axis at (0,1). What is th
timurjin [86]

Answer:

(1, 7 )

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Then the equations of the 2 lines are

y = 4x + 3 → (1)

y = 6x + 1 → (2)

Substitute y = 6x + 1 into (1)

6x + 1 = 4x + 3 ( subtract 4x from both sides )

2x + 1 = 3 ( subtract 1 from both sides )

2x = 2 ( divide both sides by 2 )

x = 1

Substitute x = 1 into either of the 2 equations for corresponding value of y

Substituting into (1)

y = 4(1) + 3 = 4 + 3 = 7

Point of intersection = (1, 7 )

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3 years ago
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1. if $2,500 is invested into an account that pays 4% interest compounded monthly how long will it take for the investment to do
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What is the probability that the toy is dressed in a polka-dotted shirt and a cowboy hat ?
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4 0
3 years ago
The tables show the number of chin-ups done by students in two different gym classes. 2nd Period 3 4 12 14 7 7 8 4 8 3 11 10 9 8
Mekhanik [1.2K]

Answer:

On average, students in the 4th period did more chin-ups than students in the 2nd period

Step-by-step explanation:

Given the table values as

2nd Period     3  4 12 14 7  7  8  4  8  3  11  10  9   8 10 4  8 7  13 9

4th Period      10 3 14 14 16 15 7 12 7  10 12  8  10  9 6  11  9 1   2 5

Find the average chin-ups done by students in the gym classes

For 2nd Period gym class, the average will be;

=sum of chin-ups ÷ number of students

=sum of chin-ups in 2nd period gym class=

=3 + 4 +12+ 14+ 7 + 7 + 8+  4 + 8 + 3+  11+  10+  9 +  8 +10+ 4+  8+ 7 + 13+ 9\\\\=159

=number of students=20

Average=159÷20

=\frac{159}{20} =7.95\\\\\\=8

For 4th Period gym class

Sum of chin-ups=

=10+ 3+ 14+ 14 +16 +15+ 7 +12 +7+ 10+ 12 +8+ 10+ 9+ 6+ 11+ 9 +1 +2 +5\\\\\\=181

Number of students=20

Average number of chin-ups in the 4th period gym class

=\frac{181}{20} =9.05\\\\\\=9

Average number of chin-ups in 2nd Period Class = 8

Average number of chin-ups in 4th Period Class= 9

Conclusion; On average students in the 4th period gym class made more chin-ups (9) than those in 2nd period gym class (8).

3 0
4 years ago
Read 2 more answers
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