Answer:
x+3 is not a factor
Step-by-step explanation:
A graphing calculator shows the expression has a zero at x=3 and no other real zeros. If x+3 were a factor, there would be a zero at x = -3.
x+3 is not a factor of the expression.
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You can check to see if x+3 is a factor by evaluating the expression for x=-3. If (x+3) is a factor, x=-3 will make the function be zero.
3(-x³ +2x² +2x +3) = 3(((-x +2)x +2)x +3) = 3(((-(-3)+2)(-3) +2)(-3) +3)
= 3((-15+2)(-3) +3) = 3(39 +3) = 126 ≠ 0
The expression evaluates to 126 at x=-3, so x+3 is NOT a factor.
Answer:
6x3=18
Step-by-step explanation:
Answer:
(x, y) ≈ (-5.89, 1.16)
Step-by-step explanation:
We assume the CD is still accelerating at the same rate at the end of the given time period. The angular position will be found from ...
θ(t) = θ₀ + (1/2)a·t²
Filling in the numbers given, we get
θ(3.51) = (10π/180) + (1/2)(2.49)(3.51²) = 15.51306 . . . radians
The x-y coordinates will be found from ...
(x, y) = radius·(cos(θ), sin(θ)) ≈ 6·(-0.981066, 0.193674)
(x, y) ≈ (-5.89, 1.16)
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For the trig functions, the calculator must be in radians mode, unless you have converted the angles to degrees.