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4 years ago

O editură produce 324000 manuale

1 answer:

6 0

Cate manuale sunt in depozit pt. fiecare dintre cele 4 clase primare?
324000/4=81000 manuale
Cate manuale se expediaza pt clasa1?
81000/3=27000manuale
Cate manuale se expediaza pt clasa2?
27000-5500=21500manuale
Cate manuale se expediaza pt clasa3?
27000+21500=48500manuale
Cate manuale se expediaza pt clasa4?
27000x3=81000
Cate manuale au ramas pt clasa1?
81000-27000=54000manuale
Cate manuale au ramas pt clasa2?
81000-21500=59500manuale
Cate manuale au ramas pt clasa3?
81000-48500=32500
Cate manuale au ramas pt clasa4?
81000-81000=0 manuale
coroana?

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Distance between a(3,9) b(-10,4)

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Answer:

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3 years ago

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What is the midpoint between -2-3i and 3+9i

Svetlanka [38]

Answer:

1/2 + 3i is the midpoint between -2-3i and 3+9i.

Step-by-step explanation:

Given the complex number

-2-3i

3+9i

The formula to find the midpoint of two complex number (a + bi) and (c + di) is:

$M=\frac{\left(a+c\right)}{2}+\frac{\left(b+d\right)i}{2}$

$M=\frac{\left(-2+3\right)}{2}+\frac{\left(-3+\left(9\right)\right)i}{2}$

$M=\frac{-2+3+\left(-3+9\right)i}{2}$

$M=\frac{1+6i}{2}$

$M=\frac{1}{2}+3i$

Therefore, 1/2 + 3i is the midpoint between -2-3i and 3+9i.

3 0

3 years ago

the mgf of a random variable x is e^3(e^t-1). Find P[mean - standard deviation squared < X < 1/2( mean + standard deviatio

postnew [5]

The given MGF is that for a random variable following a Poisson distribution with parameter $\lambda=3$ .

This means $\mathbb E(X)=\mathbb V(X)=\lambda$ , and $X$ has PMF

$f_X(x)=\begin{cases}\dfrac{3^xe^{-3}}{x!}&\text{for }x\ge0\\0&\text{otherwise}\end{cases}$

So, the desired probability is

$\mathbb P\left(\lambda-\lambda^2$

This is equivalent to

$\displaystyle\sum_{x=0}^2\mathbb P(X=x)=\sum_{x=0}^2\frac{3^x}{x!e^3}=\frac{17}{2e^3}\approx0.4232$

8 0

4 years ago

I) 43x + 31y = 98<br> 31x + 43y = 50

Neko [114]

There are no solutions to the given system of equations.

Hope this helps.

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3 years ago

Pls help with my geometry

Sati [7]

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3 years ago