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vivado [14]
2 years ago
13

HELP! I NEED AN ANSWER. IF YOUR ANSWER WAS CORRECT I WILL GIVE YOU BRAINLIEST

Mathematics
1 answer:
anzhelika [568]2 years ago
7 0

Answer:

an isos. triangle

Step-by-step explanation:

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List the following numbers in order from least to greatest. a) 3.5× 10/3 B) 3.5× 10-2 C) 5.3 × 10/3
Crazy boy [7]

Answer:

3.5*10^{-2}, 3.5*10^3, 5.3*10^3

B, A, C

Step-by-step explanation:

This is scientific notation. The numbers 3.5 * 10^3\\3.5 *10^{-2}\\5.3 * 10^3 can be ordered least to greatest by looking at their digits and exponents. Since a -2 as an exponent is present, this means this is a small decimal and is the least. 3.5 and 5.3 have the same exponent of 3 but 5.3 is greater than 3.5 so its the greatest. The order is

3.5*10^{-2}, 3.5*10^3, 5.3*10^3

5 0
2 years ago
A bag of chocolates is labeled to contain 0.384 pounds of chocolates. The actual weight of the chocolates is 0.3798 pounds. Are
Marta_Voda [28]

Based on the information given the chocolates stated on the label is 0.0042-ounce lighter.

Weight:

Using this formula

Chocolate weight=Current weight-Actual weight

Where:

Current weight=0.384

Actual weight=0.3798

Let plug in the formula

Chocolate weight=0.384-0.3798

Chocolate weight=0.0042 ounce

In conclusion, the chocolates stated on the label are 0.0042-ounce lighter.

6 0
1 year ago
Please complete part A.+ B. And show all work. Thank you for your help.
Leno4ka [110]
-3,7) yes I am pretty sure that’s the answer
3 0
3 years ago
The manager of a music store has kept records of
Marysya12 [62]

Answer:

(a) P(x\le 3) = 0.75

(b) P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

(c) P(x \ge 5) = 0.10

(d) P(x = 1\ or\ 2) = 0.55

(e) P(x > 2) = 0.45

Step-by-step explanation:

Given

\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

Solving (b): Probability of at most 3 CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x \ge 5) = P(5) + P(6\ or\ more)

This gives:

P(x\ge 5) = 0.05 + 0.05

P(x \ge 5) = 0.10

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}

This probability is calculated as:

P(x = 1\ or\ 2) = P(1) + P(2)

This gives:

P(x = 1\ or\ 2) = 0.30 + 0.25

P(x = 1\ or\ 2) = 0.55

Solving (e): Probability of more than 2 CDs

Here, we consider:

\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)

This gives:

P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05

P(x > 2) = 0.45

3 0
3 years ago
Help answering this question please
abruzzese [7]
Answer: ok
explanation:
5 0
2 years ago
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