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mamaluj [8]
3 years ago
9

Solve the equation x^4+7x^2-18=0 and express each solution in a+bi form

Mathematics
1 answer:
maw [93]3 years ago
4 0

Answer:

The following are the solutions found for x:

+√2 + 0i

-√2 + 0i

0 + 3i

0 - 3i

Step-by-step explanation:

The given equation is:

x⁴ + 7x² - 18 = 0

Rewrite x4 as (x²)²

(x²)² + 7x² − 18 = 0

Let u = x²

u² + 7u − 18 = 0

Factorize:

u² + 9u - 2u - 18 = 0

u(u+9) -2(u+9) = 0

(u-2)(u+9) = 0

(x²-2)(x²+9) = 0

Seperate both equations:

x² - 2 = 0                     x² + 9 = 0

x = ±√2                       x = ±√-9

x = ±√2                       x = ± 3√-1

x = ±√2 + 0i                x = 0 ± 3i

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Answer:

x is equal to 20 in this picture.

Step-by-step explanation:

In order to find this, we need to note that these two angles will be equal to each other. Now we can put their values equal to each other and solve for x.

3x + 50 = 6x - 10

50 = 3x - 10

60 = 3x

20 = x

6 0
3 years ago
Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
2 years ago
Read 2 more answers
The sales tax rate is 4.3064.306​% for the city and 44​% for the state. Find the total amount paid for 33 boxes of chocolates at
svp [43]

Answer:

The Total amount of of 33 boxes of chocolates including taxes is $838.358

Step-by-step explanation:

Given as :

The sales tax rate for city = 4.306%

The sales tax rate for the state = 44%

Total number of boxes = 33

The price of each chocolates = $17.13

So , The price of 33 boxes of chocolates = $17.13 × 33

I.e The price of 33 boxes of chocolates = $565.29

Now total tax including state and city =  4.306% + 44% = 48.306 %

So, The tax amount paid for 33 boxes of chocolates = 48.306 % of $565.29

∴    The tax amount paid for 33 boxes of chocolates = 48.306 % × $565.29

                                                                       = 0.48306× $565.29

                                                                       = $273.068

∴ The Total amount of of 33 boxes of chocolates including taxes = $565.29 +  $273.068 = $838.358

Hence The Total amount of of 33 boxes of chocolates including taxes is $838.358 . Answer

4 0
3 years ago
Find m&lt; A<br> inscribed angles and arcs
never [62]

Answer: 115 degrees

Step-by-step explanation:

5 0
2 years ago
4. Two friends, Sequoia and Raven, sold organic chap sticks at the local market.
Nina [5.8K]

Answer:

Sequoia sold 2 chap sticks while Raven sold 4.

Step-by-step explanation:

Since two friends, Sequoia and Raven, sold organic chap sticks at the local market, and Sequoia sold her chap sticks for $ 4 and Raven sold hers for $ 3 each, and in the first hour, their total combined sales were $ 20, if in the first hour, the friends sold a total of 6 chap sticks between them, to determine the number of chap sticks each of the friends sold during this time the following calculation must be performed:

6 x 4 + 0 x 3 = 24

5 x 4 + 1 x 3 = 23

2 x 4 + 4 x 3 = 20

Therefore, Sequoia sold 2 chap sticks while Raven sold 4.

7 0
2 years ago
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