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2 years ago

2/3(12x+30)-12=0.4(15x+10)

2 answers:

7 0

Isolate the variable by dividing each side by factors that don’t contain variable.

Answer: x = -2

Hope this helps!
Have a great day!

Dmitry_Shevchenko [17]2 years ago

5 0

Step-by-step explanation:

2/3 (12x+30)-12=4/10 (15x+10)

30×2/3 (12x+30)-12×30=4/10 (15x+10)×30

10(12x+30)-360 =12 (15x+10)

120x+300-360=180x+120

300-360-120=180x-120x

-180=60x

-180/60=60x/60

-30=x

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What are the missing terms 64, -32, 16, -8, ___, ___?

Daniel [21]

Divide by -2 for all of the numbers

64/-32=-2

-32/ 2= -16

-16/2= -8

-8/-2= 4

4/-2= -2

Answer : 4 ,-2

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3 years ago

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How to solve (x-10)(x + 10)

tensa zangetsu [6.8K]

Answer:

Multiplying/simplifying, it is x^2-100(found by the FOIL method)

Step-by-step explanation:

multiply the commons factors x times x is x squared

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3 years ago

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PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given Trigonometric expression is

$\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }$

So, on rationalizing the denominator, we get

$\rm \: = \: \dfrac{sin\theta }{1 + cos\theta } \times \dfrac{1 - cos\theta }{1 - cos\theta }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) = {x}^{2} - {y}^{2} \: }}}$

So, using this, we get

$\rm \: = \: \dfrac{sin\theta (1 - cos\theta )}{1 - {cos}^{2}\theta }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {sin}^{2}x + {cos}^{2}x = 1}}}$

So, using this identity, we get

$\rm \: = \: \dfrac{sin\theta (1 - cos\theta )}{{sin}^{2}\theta }$

$\rm \: = \: \dfrac{1 - cos\theta }{sin\theta }$

<u>Hence, </u>

$\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta } = \: \dfrac{1 - cos\theta }{sin\theta } }}} \\$

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