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3 years ago

I think I got this wrong so can someone please help me and explain it to me

Mathematics

2 answers:

Ber [7]3 years ago

3 0

Answer:

the answer is c

Step-by-step explanation:

Becuase he is given 100 dollars and he uses 20 dollars a day, so you put x with 20 to calculate how many days that he can spend $20 on

arsen [322]3 years ago

3 0

Day 1: money spent = 20

Day 2: total money spent = 20+20 = 2*20

So, for x days, total spent money should be 20*x = 20x

At an instant, say, after x days.

=> saving = total amount - spent

=> money left = 100 - 20x

=> y = 100 - 2x

=> y = - 2x + 100

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F(a) = 2a - 1 g(a) = 4a 1 Find f(a) + g(a) 6a + 2 O 6a-2 Oa+2 O 2a-2

Pavel [41]

Answer:

An aeroplanes velocity changes from 1250m/s as it comes down to land . It accelerates at 4.9m/s² . Calculate how long it took to come to a stop ?

Step-by-step explanation:

i am sorry in never answeres ur question but pls can u help me i am struggling

8 0

3 years ago

Read 2 more answers

25 Points ! Write a paragraph proof. Given: ∠T and ∠V are right angles. Prove: ∆TUW ∆VWU

vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and

including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0

3 years ago

Read 2 more answers

Please help with this, 50 points. the question is in the photo.

Alex

Answer:

Creo que es de la siguiente forma

Step-by-step explanation:

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5 0

2 years ago

Read 2 more answers

Is this factorable please help me.

olga2289 [7]

This can be factored into (2t - 9)(t + 7)

7 0

3 years ago

What is the average rate of change of f(x) = -x2 + 3x + 6 over the interval –3

Rufina [12.5K]

Answer:

$\frac{\Delta y}{\Delta x} =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3$

Step-by-step explanation:

To find the average rate of change of a function over a given interval, basically you need to find the slope. The mathematical definition of the slope is very similar to the one we use every day. In mathematics, the slope is the relationship between the vertical and horizontal changes between two points on a surface or a line. In this sense, the slope can be found using the following expression:

$Average\hspace{3}rate\hspace{3}of\hspace{3}change=Slope=\frac{y_2-y_1}{x_2-x_1} =\frac{f(x_2)-f(x_1)}{x_2-x_1}$

So, the average rate of change of:

$f(x)=-x^2+3x+6$

Over the interval $-3$

Is:

$f(x_2)=f(3)=-(3)^2+3(3)+6=-9+9+6=6\\\\f(x_1)=f(-3)=-(-3)^2+3(-3)+6=-9-9+6=-12$

$\frac{\Delta y}{\Delta x} =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3$

Therefore, the average rate of change of this function over that interval is 3.

3 0

3 years ago