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Radda [10]
4 years ago
12

Find the value of: a) 5x when x = 6 B) 3y when y = -7

Mathematics
2 answers:
Y_Kistochka [10]4 years ago
7 0

Answer:

a 30 b -21

Step-by-step explanation:

a 5x = 5(6)

= 30

b 3y = 3(-7)

= -21

galina1969 [7]4 years ago
5 0

Answer:

a,30 b,-21

Step-by-step explanation:

a, 5x = 5x6 = 30

b, 3y = 3x-7 = -21

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Total: $8415

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2 years ago
Which point lies on a circle that is centered at A(-3, 2) and passes through B(1, 3)?
My name is Ann [436]
The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the center
r - the radius

\hbox{the center: } A(-3,2) \\&#10;h=-3 \\ k=2 \\ \\&#10;\hbox{the equation:} \\&#10;(x+3)^2+(y-2)^2=r^2 \\ \\&#10;\hbox{the circle passes through B(1,3)} \\&#10;x=1 \\ y=3 \\ \Downarrow \\&#10;(1+3)^2+(3-2)^2=r^2 \\&#10;4^2+1^2=r^2 \\&#10;16+1=r^2 \\&#10;17=r^2 \\ \\&#10;\hbox{the equation is:} \\&#10;(x+3)^2+(y-2)^2=17

Plug the coordinates of the points into the equation and check:
C(-1,-2) \\&#10;(-1+3)^2+(-2-2)^2=17 \\&#10;2^2+(-4)^2=17 \\&#10;4+16=17 \\&#10;20=17 \\&#10;not \ true \\ \\&#10;D(-6,3) \\&#10;(-6+3)^2+(3-2)^2=17 \\&#10;(-3)^2+1^2=17 \\&#10;9+1=17 \\&#10;10=17 \\&#10;not \ true

E(-3,-3) \\&#10;(-3+3)^2+(-3-2)^2=17 \\&#10;0^2+(-5)^2=17 \\&#10;25=17 \\&#10;not \ true \\ \\&#10;F(-2,6) \\&#10;(-2+3)^2+(6-2)^2=17 \\&#10;1^2+4^2=17 \\&#10;1+16=17 \\&#10;17=17 \\&#10;true

The answer is F(-2,6).
8 0
3 years ago
Solve 2x-3&lt; 2<br>please answer it fast ​
murzikaleks [220]

Answer:

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Step-by-step explanation:

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2x−3 +3 <2 +3

which makes

2x<5

Divide both sides by 2.

2x/2 < 5/2

x<5/2

4 0
3 years ago
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