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2 years ago

A science class has

1 answer:

8 0

The probability that the teacher selects both boys from a seventh grader and eighth grader.
first calculate the probility that it is boy in each grade
7th
x = 7 / ( 7 + 3) = 7 / 10

8th
y = 2 / (2 + 2) = 1 / 2

so the probability
P = ( 7 / 10 ) ( 1 / 2 )
P = 0.35

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2 years ago

Write a conditional statement for a following Venn diagram

Amanda [17]

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2 years ago

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ziro4ka [17]

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3 years ago

What is the solution to the equation 2/3x+1=1/6x-7?

Alborosie

As it is, in accordance with the priorities of the operators (or the PEMDAS rule) the equation without parentheses mean
<span>(2/3)x+1=(1/6)x-7
I do not suppose you mean the above, since the solution is relatively trivial.

I suppose you actually mean
</span><span>2/(3x+1)=1/(6x-7)
in which case you would cross-multiply:
2(6x-7)=(3x-1)
and expand/distribute
12x-14=3x-1
isolate x and solve
12x-3x=-1+14
9x=13
x=13/9
If you mean the first form of equation without parentheses, my apologies.</span>

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2 years ago

Plss. pa answers ?<br><br>thanks po<br><br>

Lana71 [14]

Answer:

<h3>Graph 3</h3>

Line starting at x = -2

<u>Domain</u>: x ≥ -2
<u>Range</u>: y ≥ 0

<h3>Graph 4</h3>

Vertical line

<u>Domain</u>: x = 3
<u>Range</u>: y = any real number

<h3>Graph 5</h3>

Quadratic function with negative leading coefficient and max value of 3

<u>Domain</u>: x = any real number
<u>Range</u>: y ≤ 3

<h3>Graph 6</h3>

Curve with non-negative domain and min value of -2

<u>Domain</u>: x ≥ 0
<u>Range</u>: y ≥ -2

<h3>Graph 7</h3>

Line with no restriction

<u>Domain</u>: x = any real number
<u>Range</u>: y = any real number

<h3>Graph 8</h3>

Quadratic function with positive leading coefficient and min value of 4

<u>Domain</u>: x = any real number
<u>Range</u>: y ≥ 4

<h3>Graph 9</h3>

Parabola with restriction at x = -4

<u>Domain</u>: x = any real number except -4
<u>Range</u>: y = any real number

<h3>Graph 10</h3>

Square root function with star point (2, 0)

<u>Domain</u>: x ≥ 2
<u>Range</u>: y ≥ 0

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2 years ago