Answer:
x>4
Step-by-step explanation:
because x is greater than 4
Answer:
#9: 1.2
#10: 1.25
Step-by-step explanation:
To find the scale factor of the smaller figure to the larger figure, we're going to be dividing the measurements of corresponding edges.

If you wanted to find the scale factor of the larger figure to the smaller figure, you'd do: 
Question #9:
Left edges:
⇒
= 1.2
Bottom edges:
⇒
= 1.2
<em>(You should get the same number as long as the figures are similar.)</em>
<em />
Question #10:
Bottom edges:
⇒
= 1.25
<em>(There are no corresponding edges with measurements that we can compare.)</em>
<em />
~Hope this helps!~
Answer:
45
Step-by-step explanation:
Answer:
describe the relationship between what
Step-by-step explanation:
Step-by-step explanation:
Hey, there!!
Here, one point is A(10,8) and P(8,5) is the midpoint.
Let B(x,y) be the another end point.
Now,
Using midpoint formulae,


Since they are equal,equating with their corresponding elements we get,

or, 16 = 10 + x
or, x=16-10
Therefore, x = 6
Now,

or, 10 = 8 + y
or, y = 2
Therefore, The coordinates of another point are B(6,2)
<em><u>Hope it helps</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>