3 years ago

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

Mathematics

1 answer:

prisoha [69]3 years ago

4 0

I’m not sure I’m looking for it

You might be interested in

Help picture below problem 10

melamori03 [73]

Answer:

180-52=128

Do mark BRAINLIEST

3 0

2 years ago

Question 16

astraxan [27]

Answer:

I think the answer should be 20

5 0

3 years ago

Alessandro wrote the quadratic equation –6 = x2 + 4x – 1 in standard form. What is the value of c in his new equation?

Black_prince [1.1K]

Answer:

Step-by-step explanation:

To write it in standard form, we set the equation equal to 0. To do this, we add 6 to each side:

-6+6 = x² + 4x - 1 + 6

0 = x² + 4x + 5

The related function is

y = x² + 4x + 5

The value of c in this function is 5.

7 0

3 years ago

Convert 210 to radian measure in terms of \pi

Veronika [31]

Answer:

<h2>3.66519 radian</h2>

Step-by-step explanation:

6 0

3 years ago

THIS QUESTION IS EASY, I JUST NEED EXPLANATION.

chubhunter [2.5K]

It would help to have the question. But I'll guess

$\sqrt[4]{x^{\frac 3 5}}{\sqrt{x^2}} = ((x^{\frac 3 5})^{\frac 1 4}) }{ x} = x^{\frac 3{20}} x = x \sqrt[20]{x^3}$

2nd choice.

I forgot the explanation because I was so glad to have puzzled out the question.

The fourth root is the same as the 1/4 th power.

If we know x is positive $\sqrt{x^2}=|x|=x$

$\sqrt[4]{x^{\frac 3 5}}{\sqrt{x^2}}$

$= ((x^{\frac 3 5})^{\frac 1 4}) }{ x}$

We multiply the powers: $(a^b)^c=a^{bc}$

$= x^{\frac 3{20}} x$

The one-twentieth power is the twentieth root. We bring the additional factor of x to the front.

$= x \sqrt[20]{x^3}$

6 0

4 years ago

Read 2 more answers