Here is the answer.
use photomath for it.
it is really cool
use photomath for it.
it is really cool
I need help please due in a hour
1 answer:
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Check the picture below
notice, that running a line from the center, you end up with an angle bisector to a vertex of the triangle, now, this is a "regular polygon", so, all sides are equal, for a triangle, when all sides are equal, all angles are also equal, and since the sum of all internal angles in a triangle must add up to 180°, then that means, each angle is 60°
now, you run an angle bisector through it, you end up with a 30°, 30° split, and that gives you a 30-60-90 triangle
notice, that running a line from the center, you end up with an angle bisector to a vertex of the triangle, now, this is a "regular polygon", so, all sides are equal, for a triangle, when all sides are equal, all angles are also equal, and since the sum of all internal angles in a triangle must add up to 180°, then that means, each angle is 60°
now, you run an angle bisector through it, you end up with a 30°, 30° split, and that gives you a 30-60-90 triangle
Step-by-step explanation:
For solving, use quadratic formula
