Find (f + 1)(f^2 +4f +8).
1 answer:
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Answer:
The domain ⇒ x ∈ real number
The range ⇒ y ≥ -3
The y-intercept ⇒ (0 , -1)
Step-by-step explanation:
∵ y = 2Ix - 1I - 3
∴ y = 2(x - 1) - 3
∴ y = 2x - 2 - 3 = 2x - 5 ⇒ positive slope
∴ y = 2(-x + 1) - 3
∴ y = -2x + 2 - 3 = -2x - 1 ⇒ negative slope
∴ 2x - 5 = -2x - 1 ⇒ 4x = 4 ⇒ x = 1
∴ Y = 2(1) - 5 = -3
∴ The two lines intersect each other at (1 , -3)
∴ The domain is x ∈ real number
∴ The range is y ≥ -3
∴ The y-intercept = -1 ⇒ (0 , -1)
Answer:
( -9, -6)
Step-by-step explanation:
The red dot is the original (6, 9)
The blue dot is when it is rotated 270 degrees clockwise (-9, -6).
