Answer:
Domain : all real numbers.
Y-intercept : (0,-1)
The range is y >= -3.
Step-by-step explanation:
We have given the function:
y = 2Ix-1I -3
We have to draw the graph of this equation.
As see from the equation the domain is :
domain: all real numbers.
As we see from the graph the y-intercept is -1 (the point where x = 0)
y-intercept = (0,-1)
The range is y >= -3.
The graph is attached with the question.
Answer:
The domain ⇒ x ∈ real number
The range ⇒ y ≥ -3
The y-intercept ⇒ (0 , -1)
Step-by-step explanation:
∵ y = 2Ix - 1I - 3
∴ y = 2(x - 1) - 3
∴ y = 2x - 2 - 3 = 2x - 5 ⇒ positive slope
∴ y = 2(-x + 1) - 3
∴ y = -2x + 2 - 3 = -2x - 1 ⇒ negative slope
∴ 2x - 5 = -2x - 1 ⇒ 4x = 4 ⇒ x = 1
∴ Y = 2(1) - 5 = -3
∴ The two lines intersect each other at (1 , -3)
∴ The domain is x ∈ real number
∴ The range is y ≥ -3
∴ The y-intercept = -1 ⇒ (0 , -1)
Answer:
x=14, x=1
Step-by-step explanation:
View Image.
First factor the equation. Which numbers multiplies to 14 and adds up to -15? It's -14 and -1 so the equation is factored to (x-14)(x-1). I assume that you know how to do this.
Then set the values inside the parentheses equal to 0 and solve for x.
1. Answer (D). By the law of sines, we have in any
2. Answer (C). The law of cosines, accepts up to three sides and an angle as an input.
3. Answer (D). Although this triangle is right, we are not given enough information to uniquely determine its sides and angles - here, we need either one more side or one more angle.
4. Answer (D). Don't get tripped up by answer choice (C) - this is just a rearrangement of the statement of the law of cosines. In choice (D), the signs of and
are reversed.
5. Answer (B). By the law of sines, we have Solving gives
Note that this is the <em>ambiguous (SSA) case</em> of the law of sines, where the given measures could specify one triangle, two triangles, or none at all!
6. Answer (A). Since we know all three sides and none of the angles, starting with the law of sines will not help, so we begin with the law of cosines to find one angle; from there, we can use the law of sines to find the remaining angles.