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soldi70 [24.7K]
3 years ago
15

Mickey draws two distinct intersecting lines, p and q. Which conclusions must be true? Select three that apply.

Mathematics
2 answers:
timofeeve [1]3 years ago
7 0

Hey there!

D is the answer.

I was thinking it might be B but no one said the lines crossed each other.

Hope this helps, Jesus loves you!

igor_vitrenko [27]3 years ago
7 0

If the two lines are distinct and intersecting, then

A). They're not parallel.  (because they intersect)

B). They form four angles.

and D). They share a common point. (because they intersect)

They don't have to be perpendicular.

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Tresset [83]

<u>Answer:</u>

The correct answer option is: 4.

<u>Step-by-step explanation:</u>

We are given the following two functions and we are to find the value of ( f - g ) ( 5 ):

f(x) = x^2 - 5

g(x) = 4x - 4

Finding ( f - g ) ( x ):

( f - g ) ( x ) = (x^2-5)-(4x-4) = x^2-4x-5+4

( f - g ) ( x ) = x^2-4x-1

So, ( f - g ) ( 5 ) = (5)^2-4(5)-1 = 4

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3 years ago
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It is between 2 and 3
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BabaBlast [244]
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A baseball player had 4 hits in 8 games. At this rate, how many hits will the baseball player have in the next 28
klemol [59]

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Step-by-step explanation:

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3 years ago
Is the function continuous at x = -17
Pavlova-9 [17]

For a function to be continuous at an x-value, say -17, you need to make sure two things line up:

The limit from the left equals the limit from the right.

     \lim_{x \to -17^{-}} f(x) =  \lim_{x \to -17^{+}} f(x)

This limit equals the functions value.

    \lim_{x \to -17} f(x) = f(-17)

The left hand limit involves the first piece, f(x) = 20x + 1:

    \begin{aligned} \lim_{x \to -17^{-}} f(x) &=  \lim_{x \to -17^{-}} (20x+1)\\[0.5em]&=   20(-17)+1\\[0.5em]&=   -339\endaligned}

The right hand limit invovles the second piece, f(x) = -10x^2:

    \begin{aligned} \lim_{x \to -17^{+}} f(x) &=  \lim_{x \to -17^{+}} (-10x^2)\\[0.5em]&=   -10\cdot (-17)^2\\[0.5em]&=   -2890\endaligned}

Since the two one-sided limits don't match, the function is not continuous at x=-17.

3 0
3 years ago
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