B^5 when you’re dividing exponents, just subtract!
Well your answer for problem 4 is 28. IM not sure what the boxes are for though...
Answer:
x = 4
Step-by-step explanation:
a = i-2j
b = 2i-xj
1 = k•2
-2 = k•(-x)
=> 1/2 = k
=> (-2)/(-x) = k
=> 1/2 = (-2)/(-x) => 1/2 = 2/x => x = 4
Answer:
t = 3/2
Step-by-step explanation:
Instead of randomly guessing values of "t" that will satisfy the equation, you can easily find the correct value by solving the equation in terms of "t". In other words, you can set the equation equal to "t" to find the final answer.
(-2/3)t - 2 = -3 <----- Original equation
(-2/3)t = -1 <----- Add 2 to both sides
t = 3/2 <----- Divide both sides by -2/3
You can check this value by plugging it into "t" and determining whether both sides of the equations will be equal.
(-2/3)t - 2 = -3 <----- Original equation
(-2/3)(3/2) - 2 = -3 <----- Plug 3/2 into "t"
-6/6 - 2 = -3 <----- Multiply -2/3 and 3/2
-1 - 2 = -3 <----- Simplify -6/6
-3 = -3 <----- Subtract
Answer:
I think positive
Step-by-step explanation:
