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stich3 [128]
3 years ago
7

1st question I want to solve

Mathematics
1 answer:
mr_godi [17]3 years ago
7 0

Answer:

34.64

Step-by-step explanation:

take tan value and solve the triangle

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WILL GIVE BRAINLIEST<br> Write the product using exponents. (−9)⋅(−9)⋅(−9)⋅(−9)⋅(−9)
Daniel [21]

Answer:

-9^5

Step-by-step explanation:

(-9)*(-9)*... is -9^5

Please mark as Brainliest! :)

Have a nice day.

7 0
3 years ago
Read 2 more answers
I need help please! Step by step
nevsk [136]

The total length was 6 m.

One of the tables was 1.8 m

Subtract 1.8 from 6 to find the total length of the other two tables:

6 - 1.8 = 4.2m

The other two tables are the same size, so now divide 4.2 m by 2:

4.2 / 2 = 2.1

The other tables are 2.1 m long.

6 0
3 years ago
A small-business owner will lease a billboard to advertise her business. The table shows the linear relationship between the cos
soldi70 [24.7K]

It would take about 25 months for the cost of leasing a billboard be the same for both companies.

<h3>Linear function</h3>

A linear function is in the form:

y = mx + b

Where y,x are variables, m is the rate of change and b is the initial value of y.

Let P represent the cost to lease a billboard from a different company for x months. Given that:

P(x) = 100x

For the second company, let C represent the cost, hence using the table point (1, 580) and (5, 900):

C - 580 = [(900 - 580)/(5 - 1)](x - 1)

C = 80x + 500

For the same cost:

100x = 80x + 500

x = 25 months

It would take about 25 months for the cost of leasing a billboard be the same for both companies.

Find out more on Linear function at: brainly.com/question/15602982

4 0
2 years ago
Read 2 more answers
Is it possible to draw a triangle with side lengths 4cm 7cm And 9cm
Lana71 [14]

Answer:

it is

possible

Step-by-step explanation:

<u>sum of the two shortest sides must be greater than the third side.</u>

so

4+7 < 9

11<9

condition satisfies ,

hence proved , we can draw

7 0
3 years ago
Differentiate<br>y=tan (x^2-5x+6)​
slavikrds [6]

Use the chain rule:

<em>y</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)

<em>y'</em> = sec²(<em>x</em> ² - 5<em>x</em> + 6) × (<em>x</em> ² - 5<em>x</em> + 6)'

<em>y'</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)

Perhaps more explicitly: let <em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6, so that

<em>y(x)</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)   →   <em>y(u(x))</em> = tan(<em>u(x)</em> )

By the chain rule,

<em>y'(x)</em> = <em>y'(u(x))</em> × <em>u'(x)</em>

and we have

<em>y(u)</em> = tan(<em>u</em>)   →   <em>y'(u)</em> = sec²(<em>u</em>)

<em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6   →   <em>u'(x)</em> = 2<em>x</em> - 5

Then

<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>u</em>)

or

<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)

as we found earlier.

5 0
3 years ago
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