(2n+1)(2n-1)(n+5)
=(4n^2+2n-2n-1)(n+5)
=(4n^2-1)(n+5)
=4n^3-n+20n^2-5
4n^3+20n^2-n-5
Answer:
f(-2) = -5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 3x + 1
f(-2) is x = -2
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: f(-2) = 3(-2) + 1
- Multiply: f(-2) = -6 + 1
- Add: f(-2) = -5
Answer:
from what I know I think the answer is D_24
I believe thugs is it
4.718592e+15
Step-by-step explanation:
I think no. c is correct
if it helps you then plzz mark me brainliest
