Let A=(0,0)(x₁,x₂), B=(6,0)(x₂,y₂) and C=(0,6)(x₃,y₃)
Centroid of ΔABC is given by,
G(x,y) = [x₁+x₂+x₃/3 , y₁+y₂+y₃/3] = [0+6+0/3 , 0+0+6/3] = [2,2]
3947422086
is the answer hope it helps:)
No, she is not correct.
A "composite" is a number that can be divided evenly (no decimals) by something other than itself (43) and 1.
43 has no other numbers that can divide into it and leave it a whole number.
