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Semenov [28]
3 years ago
6

2. Salvador has 10 cards, each with one number on

Mathematics
1 answer:
Karolina [17]3 years ago
5 0

Answer:

<h2>15,120 number of ways.</h2>

Step-by-step explanation:

This is a permutation problem. Given the 10 cards with numbers 2, 3, 4,5,5,7,7,7,7,7 on it, if Salvador is going to make a row call, the number of ways he can order a row is as shown below;

Total number of cards = 10!

number of times the digit 5 was repeated = 2times

number of times the digit 7 was repeated = 5times

The number of ways he can make a row call = 10!/2!5!

= 10*9*8*7*6*5!/2*5!

=  10*9*8*7*6/2

=  10*9*8*7*3

= 15,120 different ways

Hence, the number of ways he can order the row is 15,120 number of ways.

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What is the second step in the​ construction?
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Step-by-step explanation:

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3 years ago
The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te
kozerog [31]

Answer:

\dfrac{6}{7}.

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

a_n=ar^{n-1}

a+ar=6     ...(1)

Each term is 5 times the sum of the succeeding terms.

a_n=5(a_{n+1}+a_{n+2}+...+\infty)

ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)

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Divide both sides by a.

r^{n-1}=5r^n(\dfrac{1}{1-r})    [\text{Sum of infinite GP}=\dfrac{a}{1-r}]

\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}

\dfrac{1}{r}=\dfrac{5}{1-r}

1-r=5r

1=6r

\dfrac{1}{6}=r

The common ratio is 1/6.

Put r=1/6 in (1).

a+a(\dfrac{1}{6})=6

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7a=36

a=\dfrac{36}{7}

Second term ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}

Therefore, the second term is \dfrac{6}{7}.

4 0
2 years ago
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