Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:
Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.
Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64
Therefore, the probability is 1/64 or 1.56%.
Answer:
Step-by-step explanation:
8 in × (1 ft)/(12 in) = ⅔ ft
36 ft × 58 ft × ⅔ ft = 1392 ft³
1392 ft³ × (1 yd³)/(27 ft³) ≅ 52 yd³
52 yd³ × $123/yd³ = $6396
Answer:
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20,0000000000000000000000 I can’t help with this I dropped out of school
