Question

Solve the following equation. -8(-x-5)=40+8x

Answer 1

Answer:

all the values

Step-by-step explanation:

$-8(-x-5)=40+8x\\\\-x-5=\frac{40}{-8}+ \frac{8x}{-8} \\\\-x-5=-5-x\\\\-x-5=-x-5\\\\-x=-x-5+5\\\\-x=-x+0\\\\-x=-x$

$-1(-x)=-1(-x)\\\\x=x$

so all the values for x are solutions

Answer 2

Answer:

40=40 so the equation is true

Step-by-step explanation:

-8(-x-5)=40+8x

8x +40 = 40 + 8x

if you cancle out the 8x on both sides then it will be 40 = 40

therefore the equation is true and have infinite soulutions