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3 years ago

14

Mechanic charges $55 for the first hour and $50 for each additional hour how much does he charge if it takes him in four hours t

o make a repair

2 answers:

VMariaS [17]3 years ago

8 0

Answer:

440$

Step-by-step explanation:

55 x 4=220

50 x 4=200

440$

I hope this is correct if not im sorry

dolphi86 [110]3 years ago

5 0

Answer:

$ 205

Step-by-step explanation:

55+50x

x= number of hours minus the first hour (3)

so 55+50(3) = $205

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Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

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4 years ago

Solve and explain <br><br> 8-1/4n>20

Tpy6a [65]

Answer:

Step-by-step explanation:

add 8 to both side

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4 years ago

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Vesnalui [34]

Answer:

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Step-by-step explanation:

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3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

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3 years ago