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Vitek1552 [10]
3 years ago
9

Explain why the order of the coordinates does not matter when calculating length in geometry?

Mathematics
2 answers:
Norma-Jean [14]3 years ago
7 0
A=(x_1,y_1)\ \ \ and\ \ \ B=(x_2,y_2)\\\\|AB|= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} =\\\\= \sqrt{[-(x_2-x_2)]^2+[-(y_2-y_1)]^2}=\\\\ =\sqrt{(x_2-x_2)^2+(y_2-y_1)^2}=|BA|
grin007 [14]3 years ago
3 0
P(x_1;\ y_1);\ Q(x_2;\ y_2)\\\\|PQ|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\|QP|=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}=\sqrt{[-1(x_2-x_1)]^2+[-1(y_2-y_1)]^2}\\\\=\sqrt{(-1)^2(x_2-x_1)^2+(-1)^2(y_2-y_1)^2}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\|PQ|=|QP|
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5x2 this answer is for my brother only my next answer will be everyone's
ikadub [295]

Answer:

the answer is 10

Step-by-step explanation:

because 5+5=10 or 5x2=10

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2/5 x 3 as a fraction
Svet_ta [14]

Answer:

1   1/5

Step-by-step explanation:

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P(x)=(x-2)(x-4)(x-5)
Cerrena [4.2K]

The constants of a polynomial is the term that has no variable attached to it.

<h3>The constant term</h3>

To determine the constant, we simply multiply the constant term in each factor of the polynomial.

So, we have:

<h3 /><h3>Polynomial P(x) = (x-2)(x-4)(x-5)</h3>

Constant = -2 \times -4 \times -5

Constant = -40

Hence, the constant is -40

<h3>Polynomial P(x) = (x-2)(x-4)(x+5)</h3>

Constant = -2 \times -4 \times 5

Constant = 40

Hence, the constant is 40

<h3>Polynomial P(x) =1/2(x-2)(x-4)(x+5)</h3>

Constant = \frac 12 \times -2 \times -4 \times 5

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Hence, the constant is 20

<h3>Polynomial P(x) = 5(x-2)(x-4)(x+5)</h3>

Constant = 5 \times -2 \times -4 \times 5

Constant = 200

Hence, the constant is 200

<u>P(x) =-5(x-2)(x-4)(x+5)</u>

Constant = -5 \times -2 \times -4 \times 5

Constant = -200

Hence, the constant is -200

Read more about polynomials at:

brainly.com/question/2833285

5 0
2 years ago
31=4-9y I need help sorry
Drupady [299]

Answer:

y=-3

Step-by-step explanation:

31=4-9y

9y=4-31

9y=-27

y=-27/9

y=-3

8 0
3 years ago
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