Explain why the order of the coordinates does not matter when calculating length in geometry?

2 answers:

7 0

$A=(x_1,y_1)\ \ \ and\ \ \ B=(x_2,y_2)\\\\|AB|= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} =\\\\= \sqrt{[-(x_2-x_2)]^2+[-(y_2-y_1)]^2}=\\\\ =\sqrt{(x_2-x_2)^2+(y_2-y_1)^2}=|BA|$

grin007 [14]3 years ago

3 0

$P(x_1;\ y_1);\ Q(x_2;\ y_2)\\\\|PQ|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\|QP|=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}=\sqrt{[-1(x_2-x_1)]^2+[-1(y_2-y_1)]^2}\\\\=\sqrt{(-1)^2(x_2-x_1)^2+(-1)^2(y_2-y_1)^2}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\|PQ|=|QP|$

You might be interested in

A certificate of deposit with principal $150 earns 4% annual interest for 2 years. Select all the options that would earn the sa

ladessa [460]

Answer:

a,c

Step-by-step explanation:

You would get $12 in the certificate of deposit, and

a. 12

b. 13.5

c. 12

d. 8

e. 24

so, a and c

Hope this helps!

Let me know if it does and if the answer is right

8 0

2 years ago

Jane cuts a foam block along the red line. When she looks at the newly

mr_godi [17]

Answer:

B. A rectangle, 4 in by 3 in

Step-by-step explanation:

The foam has the shape of a cuboid with base of 10 in by 4 in and height of 3 in.

The foam has a front elevation of a rectangle with dimension of 4 in by 3 in. It has a left elevation of dimension 10 in by 3 in and a plan of dimension 10 in by 4 in.

If the foam is cut along the red line, the exposed face would be the same as the shape of the front elevation. Hence the shape of the cross section would be a rectangle with dimension of 4 in by 3 in.