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3 years ago

How can you model a geometry figure to solve real-world problems?

Mathematics

1 answer:

notsponge [240]3 years ago

4 0

Answer:

laying tile

Step-by-step explanation:

If you have to lay tile you are using whatever geometric shape the tile is and you have to solve a real world problem by laying the tile.

Does this help?

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Forth time I had to ask this!!

lubasha [3.4K]

A.) Yes you can, the expression would be (2.95 x Y) + 4 = X
B.) (2.95 x 24) + 4 = $74.80
C.) (2.95 x 57) + 4 = X
2.95 x 57 = 168.15 + 4 = 172.15
so basically they can buy 57 books without going over $175

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3 years ago

Adam tried to compute the average of his 7 test scores. He mistakenly divided the correct sum of all of his test scores by 6, wh

Harman [31]

Adam got the sum of his grades right, but he divided that correct figure by 6, getting 84 Before that division, the sum of his grades must have been 84 * 6, or 504. He should have divided 504 by 7, getting 72. Answer: His correct average test score is 72.

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3 years ago

Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (3, 1, 0) and perpendicu

iren2701 [21]

Answer with Step-by-step explanation:

We are given that a point (3,1,0)

Two vectors are

A=<1,1,0>

B=<0,1,1>

$A\times B=\begin{vmatrix}i&j&k\\1&1&0\\0&1&1\end{vmatrix}$

$A\times B=i-j+k$

Let v $=A\times B=i-j+k$

$v==$

$r_0==$

$r=r_0+vt$

Substitute the values then we get

$r=+t$

$r=$

The parametric equation of the line

$x=x_0+at,y=y_0+bt,z=z_0+ct$

Using the formula

The parametric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by

$x=3+t,y=1-t,z=t$

The symmetric equation of the line is given by

$\frac{x-x_0}{a}=\frac{y-y_0}{b}=\frac{z-z_0}{c}$

Using the formula

The symmetric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by

$\frac{x-3}{1}=\frac{y-1}{-1}=z$

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4 years ago

What is the apparent solution to the system of equations?

Alexus [3.1K]

X = 3
y = -3

You will see this using any graphing tool at your disposal.

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4 years ago

Help meeee with this questionnnnnnnnnn!!!!!!!!!!!!

Dafna1 [17]

Given:

The scale factor between two circles is $\dfrac{2x}{5y}$ .

To find:

The ratio of their areas.

Solution:

We know that, all circles are similar.

The ratio of the areas of similar figures is equal to the ratio of squares of their corresponding sides or equal to the square of ratio of their corresponding sides.

The scale factor is the ratio of the corresponding sides.

Ratio of areas of circles = Square of scale factor between two circles

$\text{Ratio of areas of circles}=\left(\dfrac{2x}{5y}\right)^2$

$\text{Ratio of areas of circles}=\dfrac{(2x)^2}{(5y)^2}$

$\text{Ratio of areas of circles}=\dfrac{4x^2}{25y^2}$

Therefore, the correct option is D.

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3 years ago