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9966 [12]
4 years ago
3

9r^2 - 5r -10 FACTORING QUADRATIC EXPRESSIONS

Mathematics
1 answer:
Fiesta28 [93]4 years ago
7 0
This is an irreducible quadratic.
The constant, by multiplying the first and last terms. In this equation, it is found like this:
9*-10=-90
Now, in order for it to be factored, two factors of -90 must be equal to -5.
Since there are no two factors of -90 that equal -5, this is an irreducible quadratic.
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Marcia has 412 flowers for centerpieces she uses 8 flowers for each center how many center pieces can she make
a_sh-v [17]

Answer:

5l.5

Step-by-step explanation: 412 divieded into 8 is 51 or 51.5

5 0
3 years ago
Read 2 more answers
Write an equivalent expression using distributive property and simplify for each question
Lana71 [14]

Answer:

Check explanations

Step-by-step explanation:

For all real numbers a,b, and c, the distributive property states that:

a(b + c) = ab + ac

For Part A, we have

2x + 10x = x(2 + 10) = x(12) = 12x

Or

2x + 10x = 2x(1 + 5) = 2x(6) = 12x

For Part B, we have

-4(3x-10)+5(2-6x)=-4*3x--4*10+5*2-5*6x

This simplifies to:

-4(3x-10)+5(2-6x)=-12x+40+10-30x

-4(3x-10)+5(2-6x)=-12x-30x+40+10

-4(3x-10)+5(2-6x)=-42x+50

For the C part, we have:

2(x - 4) + x = 2 \times x - 2 \times 4 + x

2(x - 4) + x = 2x - 8+ x

2(x - 4) + x = 3x - 8

For Part D, we have:

-3-7(3-4x)+8x =  - 3 - 7 \times 3  - 7 \times  - 4x + 8x

We simplify to get:

-3-7(3-4x)+8x =  - 24+28x + 8x

Simplify further to get:

-3-7(3-4x)+8x =-24+36x

4 0
4 years ago
A company compiles data on a variety of issues in education. In 2004 the company reported that the national college​ freshman-to
nasty-shy [4]

Answer:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

Step-by-step explanation:

For this case we know that we have a sample of n = 500 students and we have a percentage of expected return for their sophomore years given 66% and on fraction would be 0.66 and we are interested on the distribution for the population proportion p.

We want to know if we can apply the normal approximation, so we need to check 3 conditions:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

And we can use the empirical rule to describe the distribution of percentages.

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

8 0
4 years ago
Solve the following automotive-services problems based on the examples shown previously.
Ghella [55]
V=IR so....0.1*60 = 6 V
5 0
3 years ago
Read 2 more answers
The equation c= 0.25n can be used to find the cost (c) of buying n number of apples.
aksik [14]

Answer:

(a) The constant of proportionality is 0.25

(b) 1 apple = $0.25

(c) $3 = 12 apples

Step-by-step explanation:

Given

c= 0.25n

Solving (a): The constant of proportionality;

For an equation:

c=kn

Where

k = constant of proportionality

By comparing: c=kn to c= 0.25n

k = 0.25

Hence, the constant of proportionality is 0.25

Solving (b): What information does k = 0.25 gives.

It represents the unit rate.

<em>So, it means that 1 apple costs $0.25</em>

<em></em>

Solving (c): Number of apples for $3.

This means that c = 3

Substitute 3 for c in c= 0.25n

3 = 0.25n

Make n the subject

n = \frac{3}{0.25}

n = 12

7 0
3 years ago
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