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3 years ago

PLEASE HELP!!!! ¡¡It's for today!!

Mathematics

1 answer:

baherus [9]3 years ago

4 0

3x-5y=5

4x+y=-1

3x-5y=5

20x+5y=-5

23x=0

x=0

4(0)+y=-1

0+y=-1

y=-1

Answer for A is (0,-1)

y=2x-3

y=(x-3)/2

2x-3=(x-3)/2

4x-6=x-3

3x-6=-3

3x=3

x=1

y=2(1)-3

y=2-3

y=-1

Answer for B is (1,-1)

3x+2y=4

5x-2y=4

8x=8

x=1

3(1)+2y=4

3+2y=4

2y=1

y=1/2

Answer for C is (1,0.5)

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P+n=131p+3.26n=248.52

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Answer

Solution:

p = 79

n = 52

Step-by-step explanation:

Given equations:

A) $p+n=131$

B) $p+3.26n=248.52$

To solve for $p$ and $n$

Naming the first equation as A and second as B.

Using elimination method to solve.

In order to eliminate $p$ we subtract equation A from B.

Subtracting A from B i.e [ $B-A$

(B) $p+3.26n=248.52$

- (A) $p+n=131$

We get, $3.26n-n=248.52-131$

$2.26n=117.52$

Dividing both sides 2.26.

$\frac{2.26n}{2.26}=\frac{117.52}{2.26}$

∴ $n=52$

We can solve for $p$ by substituting $n=52$ in equation A.

$p+52=131$

Subtracting both sides by 52.

$p+52-52=131-52$

∴ $p=79$

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