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zepelin [54]
2 years ago
10

Find x to the nearest tenth. A. 0.7 B. 1.0 C. 1.1 D. 1.4

Mathematics
2 answers:
vodomira [7]2 years ago
4 0

the answer would be d. 1.4

kramer2 years ago
3 0

Answer:

D

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos33° = \frac{adjacent}{hypotenuse} = \frac{1.2}{x}

Multiply both sides by x

x × cos33° = 1.2 ← divide both sides by cos33°

x = \frac{1.2}{cos33} ≈ 1.4 ( to the nearest tenth ) → D

You might be interested in
1)a-19=3 2) y/7=10 3)5g=100 solve please
3241004551 [841]
Are these three different questions? if so:
1: add 19 to both sides to get a = 3 +19
answer: a = 22

2: multiply both sides by 7 to get y = 10 * 7
answer: y = 70

3: divide both sides by 5 to get g = 100/5
answer: g = 20

hope this helped! good luck :)
6 0
3 years ago
An Iphone 6S costs $449. There is a discount of 15%. What is the new cost?
AnnyKZ [126]

Answer:

$381.65

Step-by-step explanation:

Multiply $449 by 0.15, then subtract your answer from the original number.

4 0
3 years ago
Read 2 more answers
Find the value of :[5x+y+z][5x+y+z][5x+y+z]
KIM [24]

Answer:

Step-by-step explanation:

(a + b + c)³ = a³ + b³ + c³ + 3a²b + 3a²c + 3ab² + 3cb² +3 ac² + 3bc² + 6abc

a = 5a  ;  b =y   ; c = z

(5x + y + z)(5z + y + z )(5z + y +z) = (5x + y +z)³

= (5x)³ + y³ +z³ + 3(5x)²y + 3(5x)²z + 3(5x)*y² + 3*z*y² + 3*5x*z² + 3*y*z² + 6*5x*y*z

= 125x³ + y³ +z³ + 3*25x²y + 3*25x²*z + 15xy² + 3zy² + 15xz² + 3yz² + 35xyz

= 125x³ + y³ + z³ + 75x²y + 75x²z + 15xy² + 3zy² + 15xz² + 3yz² + 35xyz

6 0
2 years ago
1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav
OLga [1]

Answer:

(1) y=C, C\neq0

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant,  C \neq 0, has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

\Rightarrow x=C, where C\neq0.

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0
3 years ago
Would this be Side Side side
kifflom [539]

Answer:

yes

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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