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3 years ago

Factor a number, variable, or expression out of the trinomial shown below:

Mathematics

2 answers:

Roman55 [17]3 years ago

7 0

Answer:

C. 3(2x2 – 4x + 3)

Step-by-step explanation:

6x^2 – 12x + 9

We can factor out a 3

3(2x^2 -4x+3)

stellarik [79]3 years ago

4 0

Answer:

c. 3(2x^2-4x+3)

Step-by-step explanation:

The numbers 6, 12, and 9 are all multiples of 3. Divide everything by three, move it to the outside. There are no more common factors between all 3 terms so the trinomial is completely factored. Hope this helped, if not then I apologize.

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Analyze the pre-image ABCD. What are the vertices of the final image if T–1, –2 ◦ ry = x is applied to figure ABCD? A'' B''(3, 2

Katen [24]

No one will understand if you don't add the picture but the answer from Edgenuity is

A: (3,0)

B: (3,2)

C: (1,1)

D: (1,-1)

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3 years ago

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If your bank charges an out-of-network service fee of $3.00, and you withdraw $20 from each of three out-of-network ATMs, how mu

kap26 [50]

It is $69 because if every time you withdraw money you get $3 and you took $20 out 3 times that 20x3 is 60 and then plus $3x3 is nine add it all together it is $69

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3 years ago

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Complete the

nydimaria [60]

Answer:

8th: 23

11th: 32

15th: 44

22nd: 65

18th: 53

Step-by-step explanation:

The pattern is adding 3 each time:

2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41, 44, 47, 50, 53, 56, 59, 62, 65

Hope it helps!

4 0

3 years ago

In the air, it had an average speed of 16 1616 m/s m/sstart text, m, slash, s, end text. In the water, it had an average speed o

Diano4ka-milaya [45]

Answer:

t_a = 7 s

t_w = 5 s

Step-by-step explanation:

Given:

- The average speed in air v_a = 16 m/s

- The average speed in water v_w = 3 m/s

- The total distance D = 127 m

- The total time T = 12 s

Find:

How long did the stone fall in air and how long did it fall in the water?

Solution:

- Lets time taken by stone to drop through air as t_a = t_a.

- The time taken in water would be t_w = (12 - t_a)

- The total distance covered can be calculated as:

D = v_a*t_a+ v_w*(12 - t_a)

127 = 16*t_a + 3*(12 - t_a)

Simplify and solve for t:

91 = 16*t_a - 3t_a

13*t_a = 91

t_a = 7 s

t_w = 5 s

8 0

3 years ago

Can you please help me find the area? Thank you. :)))

Phoenix [80]

The figure shown in the picture is a rectangular shape that is missing a triangular piece. To determine the area of the figure you have to determine the area of the rectangle and the area of the triangular piece, then you have to subtract the area of the triangle from the area of the rectangle.

The rectangular shape has a width of 12 inches and a length of 20 inches. The area of the rectangle is equal to the multiplication of the width (w) and the length (l), following the formula:

$A=w\cdot l$

For our rectangle w=12 in and l=20 in, the area is:

$\begin{gathered} A_{\text{rectangle}}=12\cdot20 \\ A_{\text{rectangle}}=240in^2 \end{gathered}$

The triangular piece has a height of 6in and its base has a length unknown. Before calculating the area of the triangle, you have to determine the length of the base, which I marked with an "x" in the sketch above.

The length of the rectangle is 20 inches, the triangular piece divides this length into three segments, two of which measure 8 inches and the third one is of unknown length.

You can determine the value of x as follows:

$\begin{gathered} 20=8+8+x \\ 20=16+x \\ 20-16=x \\ 4=x \end{gathered}$

x=4 in → this means that the base of the triangle is 4in long.

The area of the triangle is equal to half the product of the base by the height, following the formula:

$A=\frac{b\cdot h}{2}$

For our triangle, the base is b=4in and the height is h=6in, then the area is:

$\begin{gathered} A_{\text{triangle}}=\frac{4\cdot6}{2} \\ A_{\text{triangle}}=\frac{24}{2} \\ A_{\text{triangle}}=12in^2 \end{gathered}$

Finally, to determine the area of the shape you have to subtract the area of the triangle from the area of the rectangle:

$\begin{gathered} A_{\text{total}}=A_{\text{rectangle}}-A_{\text{triangle}} \\ A_{\text{total}}=240-12 \\ A_{\text{total}}=228in^2 \end{gathered}$

The area of the figure is 228in²

8 0

1 year ago