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3 years ago

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The data show the hourly earnings (in dollars) of a sample of 25 railroad equipment manufacturers. Use technology to answer par

ts (a) and (b). 15.65 18.80 14.60 15.75 14.35 13.95 17.45 17.50 13.85 14.25 19.05 15.30 15.25 19.40 15.90 16.45 16.25 15.25 15.10 19.05 15.25 16.20 17.70 18.45 15.25

1 answer:

AleksandrR [38]3 years ago

8 0

Add me on epic games @SONOFTAM05 1v1 on fortnite buddy

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Oliver sewed a quilt 3 2/3 feet long and 2 1/4 feet wide. what is the area of her quilt?

Hunter-Best [27]

Answer:

8.25 feet

Step-by-step explanation:

3 2/3 times 2 1/4 equals 8.25

4 0

3 years ago

Katrina is shopping for berries that cost $2.19 per pound. She has 4.5 pounds of raspberries and 3.25 pounds of blueberries in h

slega [8]

2.19 2.19 9.855 + 7.1175 = (approximately) <u>$16.97</u>
x 4.5 x 3.25
----------- ----------
9. 855 7.1175
I hope this helps!!

8 0

3 years ago

Read 2 more answers

Find 415 of 619 in simplest form,

Finger [1]

Answer:

415/619

Step-by-step explanation:

619 is a prime number, so the fraction is in simplest form already.

8 0

3 years ago

(PERSON WHO ANSWERS WILL BE MARKED BRAINLIEST) Timothy has begun selling copies of his first work of art. In the first year, he

tresset_1 [31]

Y = 40
Since,
1st year = 200
2nd year= 200 + 40 =240
3rd year = 240 + 40 = 280
4th year = 280 + 40 = 320
5th year = 320 + 40 =360
6th year = 360 + 40 = 400.
So, basically all you have to do is add 40!
Therefore, the answer is y = 40 Hope this helped! :)

6 0

3 years ago

Find the linear approximation of the function g(x) = 3 1 + x at a = 0. g(x) ≈ Correct: Your answer is correct. Use it to approxi

EleoNora [17]

Answer:

$3.296x+3$

2.835

3.330

Step-by-step explanation:

$g(x) = 3^{1+x}$

Let the linear approximation be L(x) at a = 0. This is given by

$L(x) = g(a) + g'(a)(x-a)$

$g'(x)$ is the derivative of $g(x)$ . To find this, we use the form

If $f(x) = a^x$ , then $f'(x) =a^x\ln a$

By doing this and applying chain rule for the power (which is a function of x), we have

$g'(x) = 3^{1+x}\ln 3$

Then

$g'(0) = 3^{1+0}\ln 3 = 3.296$

Also $g(0) = 3^{1+0} = 3$

Hence $L(x) = 3+(x-0)\times3.296 = 3.296x + 3$

For $3^{0.95}$ , $1+x = 0.95$ and $x=-0.05$

Using this in $L(x)$ ,

$3^{0.95} = 3.296(-0.05) + 3 = 2.835$

For $3^{1.1}$ , $1+x = 1.1$ and $x=0.1$

Using this in $L(x)$ ,

$3^{1.1} = 3.296(0.1) + 3 = 3.330$

7 0

4 years ago