= 3(4a^2 + 4a - 3) - 4a^2 + 28
= 12a^2 + 12a - 9 - 4a^2 + 28
= 8a^2 + 12a + 19
= 4a(2a + 3) + 19
We have the following equation:
<span> h(t)=-4.92t^2+17.69t+575
</span> For the domain we have:
<span> </span>We match zero:
-4.92t ^ 2 + 17.69t + 575 = 0
We look for the roots:
t1 = -9.16
t2 = 12.76
We are left with the positive root, so the domain is:
[0, 12.76]
For the range we have:
We derive the function:
h '(t) = - 9.84t + 17.69
We equal zero and clear t:
-9.84t + 17.69 = 0
t = 17.69 / 9.84
t = 1.80
We evaluate the time in which it reaches the maximum height in the function:
h (1.80) = - 4.92 * (1.80) ^ 2 + 17.69 * (1.80) +575
h (1.80) = 590.90
Therefore, the range is given by:
[0, 590.9]
Answer:
the domain and range are:
domain: [0, 12.76] range: [0, 590.9]
Answer:
c =4 4/9 minutes
Step-by-step explanation:
The formula is
1/a + 1/b = 1/c where a and b is the time for each working alone and c is the time working together
1/8 + 1/10 = 1/c
Multiply by 40c to clear the fractions ( 40c is the least common multiple)
40c(1/8 + 1/10 = 1/c)
5c + 4c = 40)
9c = 40
Divide by 9
9c/9 = 40/9
c =4 4/9 minutes
Answer:
length = 20 mt
Width = 16 mt
Step-by-step explanation:
Let the length of the field be x
width of the field be y
Hence formula of the perimeter is given as
P=2(x+y)
P=72(given)
72=2(x+y)
Dividing both sides by 2 we get
x+y=36---(A)
Also given that width of the parallelogram is 4 meters less than its length
Hence
y=x-4
or x-y=4 ---(B)
Adding A and B
2x=40
x=20
y=x-4
y=20-4=16
Hence length = 20 mt
Width = 16 mt
Answer:
18/30=3/5
Step-by-step explanation:
