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Andru [333]
3 years ago
15

4 to the seventh power over 5 squared all raised to the third power

Mathematics
2 answers:
Advocard [28]3 years ago
4 0

\bf \left( \cfrac{4^7}{5^2} \right)^3\implies \stackrel{\textit{distributing the exponent}}{\left( \cfrac{4^{7\cdot 3}}{5^{2\cdot 3}} \right)}\implies \cfrac{4^{21}}{5^6}\implies \cfrac{4398046511104}{15625}

Komok [63]3 years ago
3 0

(4^7 / 5^2)^3

= 4^21 / 5^6

Answer

4^21 / 5^6

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Two or more lines are parallel when they lie in the same plane and never intersect. The symbol for parallel is <span>||</span>. To mark lines parallel, draw arrows <span>(>)</span> on each parallel line. If there are more than one pair of parallel lines, use two arrows <span>(<span>>></span>)</span> for the second pair. The two lines below would be labeled <span><span><span>AB</span><span>←→</span></span> || <span><span>MN</span><span>←→−</span></span></span> or <span>l || m</span>.

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a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

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Empirical Rule:

  • Also known as 68-95-99.7 rule.
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a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

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