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Andru [333]
3 years ago
15

4 to the seventh power over 5 squared all raised to the third power

Mathematics
2 answers:
Advocard [28]3 years ago
4 0

\bf \left( \cfrac{4^7}{5^2} \right)^3\implies \stackrel{\textit{distributing the exponent}}{\left( \cfrac{4^{7\cdot 3}}{5^{2\cdot 3}} \right)}\implies \cfrac{4^{21}}{5^6}\implies \cfrac{4398046511104}{15625}

Komok [63]3 years ago
3 0

(4^7 / 5^2)^3

= 4^21 / 5^6

Answer

4^21 / 5^6

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Curtis threw 15 darts at a dartboard.40% of his darts hit the bull’s eye.how many darts not hit the bulls eye?
Harlamova29_29 [7]

Answer:

9

Step-by-step explanation:

The number of darts that failed to hit the bulls eye is 40% of 15 subtracted from 15

Since 40% of the darts hit the bulls eye .

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40% of 15

40/100 x 15

0.4 x 15

6

This means that 6 darts hit the bulls eye.

Therefore,number of darts that did not hit the bulls eye is

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9 darts failed to hit the bulls eye

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Answer:

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Step-by-step explanation:

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3 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

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klasskru [66]

Answer:

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Step-by-step explanation:

1.  sqrt(10y^2)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(y^2) sqrt(10)

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We take the absolute  value of y because -y*-y = y^2 and the principle square root is y

2.  sqrt(x^3)

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3 years ago
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