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Marizza181 [45]
3 years ago
8

What is the domain and range of the function: f(x)= the square root of x

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

Domain: x=(0,∞)

Range: f(x)=(-∞,∞)

Step-by-step explanation:

For the domain:

The square root of a number is defined in real numbers only for positive numbers.

For the range:

The square root of a number could be positive or negative with any restriction. For example, \sqrt{25} could be 5 or -5.

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Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)
Fantom [35]

Answer:

Given: \sin(x) = (4/5).

Assuming that 0 < x < 90^{\circ}, \cos(x) = (3/5) while \tan(x) = (4/3).

Step-by-step explanation:

By the Pythagorean identity \sin^{2}(x) + \cos^{2}(x) = 1.

Assuming that 0 < x < 90^{\circ}, 0 < \cos(x) < 1.

Rearrange the Pythagorean identity to find an expression for \cos(x).

\cos^{2}(x) = 1 - \sin^{2}(x).

Given that 0 < \cos(x) < 1:

\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}.

Hence, \tan(x) would be:

\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}.

7 0
2 years ago
Which is the graph of f(x)=4(1/2)^x
dusya [7]

It would be the first graph because it lands on -1 and +4

7 0
4 years ago
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Marta is solving the equation S = 2Πrh + 2Πr2 for h. What is the result?
yulyashka [42]
<span>S = 2Πrh + 2Πr2
Manipulating the equation for h.
Step 1. subtract </span><span>2Πr2 on both sides.

</span>S - 2Πr2 = 2Πrh + 2Πr2 - 2Πr2
S - 2Πr2 = <span>2Πrh
</span>
Step 2 . divide <span>2Πr on both sides
</span>
(S - 2Πr2)/2Πr = 2Πrh/<span>2Πr

</span><span>h = </span>(S - 2Πr2)/2Πr
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4 years ago
Please helppppppppppppppppppppppppppppp
Jobisdone [24]

Answer:

54

Step-by-step explanation:

angle A+angle B+Angle C =180 degree [ angle sum property of a triangle]

36 +90 + angle B =180 degree

126 +angle B =180 degree

angle B= 180-126

54 degree

Ans

5 0
3 years ago
Factor the GCF: −12x4y − 9x3y2 + 3x2y3 (5 points)
garri49 [273]
-12x4y - 9x3y^2 + 3x^2y^3 = 3xy(-16 -9y + xy^2)
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