10000 digits can be used for 4 digit A.T.M code.
<u>Solution:</u>
Given that A.T.M required 4 digit codes using the digits 0 to 9.
Need to determine how many four digit code can be used.
We are assuming that number starting with 0 are also valid ATM codes that means 0789 , 0089 , 0006 and 0000 are also valid A.T.M codes.
Now we have four places to be filled by 0 to 9 that is 10 numbers
Also need to keep in mind that repetition is allowed in this case means if 9 is selected at thousands place than also it is available for hundreds, ones or tens place .
First digit can be selected in 10 ways that is from 0 to 9.
After selecting first digit, second digit can be selected in 10 ways that is 0 to 9 and same holds true for third and fourth digit.
So number of ways in which four digit number is created = 10 x 10 x 10 x 10 = 10000 ways
Hence 10000 digits can be used for 4 digit A.T.M code.
Answer:
f = 
Step-by-step explanation:
1. 4(4f - 9) = -(2-f) distribute the negative
2. 4(4f - 9) = -2 + f Distribute the 4
3. 16f - 9 = -2 + f Subtract f on both sides
4. 15f - 9 = -2 Add 9 on both sides
5. 15f = 7 Divide both equations by 15
6. 
f =
3/4 is as simple as it gets 5/10- 1/2
Whattttttt!!!!!!!!!!!!!!!!!
Answer:
=−4.4x^8+3.6x^5−35x^4+5x+37
Step-by-step explanation:
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