Answer:
All real numbers
Step-by-step explanation:
1. Distribute the 2 on the right side of the inequality.
2. Cancel out the 2p on both sides of the equation since they are equal.
The statement above is always true, meaning that p can be all real numbers, therefore having all real solutions.
The answer for the following question is 12i.
b is two fifths of c, so we make this a ratio with c = 1.
The ratio of b:c is 2/5 : 1
We also have 4a = 3c, rewrite this ratio so c is 1 by dividing both sides by 4,
so we get the ratio of a to c as 3/4 : 1
Now we get the a:b:c ratio of 3/4 : 2/5 : 1 now we can change the fractions to whole numbers, first by multiplying the 3 numbers by 4 to get get rid of the denominator of 4 in a:
3 : 8/5 : 4
Now multiply the 3 numbers by 5 to remove the denominator of 5 in b:
15 : 8 : 20
Now we can check using the equations:
b is 2/5 of c: 20 x 2/5 = 40/5 = 8 This is true.
4a = 3c: 4(15) = 3(20) = 60 = 60, this is also true.
The ratios is 15 : 8: 20
