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3 years ago

When does a barbershop quartet have 16 legs?

1 answer:

6 0

When Tenors are seated and the basses standing ? XD

2 chairs will give eight additional legs to the quartet.

Hope this helps

You might be interested in

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago

Royce has $15 with him and spends $12 to buy his favorite comics. He has $3 left, which he deposits in the bank. Which number wi

Sonja [21]

Answer:

C: +3

Step-by-step explanation:

We know this because Royce added money to his bank account, not subtract (b). The other options are just there to confuse you.

I hope this helps!!

6 0

3 years ago

Read 2 more answers

The temperature was 102 F. Two hours later it was 3 lower .what was his temperature then

iren [92.7K]

Answer:

99 F

Step-by-step explanation:

"Three lower" means it was the original temperature - 3, so if the original temperature was 102, we have the equation:

102 - 3

99 F

so 99 F is the answer

5 0

3 years ago

Find the indicated term of the given arithmetic sequence. a1 = 115, d = 8, n = 14

olya-2409 [2.1K]

I took the same test and I put the answer D. 1487 and I got it wrong. The correct answer was
A.3

3 0

3 years ago

The mass of a particular substance is known to grow exponentially at a rate of 1.5% per day. Its initial mass was 230 grams and,

Papessa [141]

Answer:

23 days

Step-by-step explanation:

Given that the mass of a particular substance is known to grow exponentially at a rate of 1.5% per day

Initial mass = $230 gm$

After t days, mass = $325 gm$

The equation is

$P(t) = 325 = 230 (1+\frac{1.5}{100} )^t\\\frac{325}{230} =1.015^t\\log 1.413 = t log 1.015\\t = \frac{log 1.413}{log 1.015} =\frac{0.1502}{0.0065} \\=23.229$

Approximately after 23 days the mass will become 325 gms.

7 0

4 years ago