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3 years ago

Help me on my math please

Mathematics

1 answer:

scoray [572]3 years ago

7 0

1) 9m

2) 1/64

3) 50d^3

4) pq^2 (p-q) (p-q)

= pq^2 ( p^2 - 9p -9p +18)

= pq^4 - 18p^2q^2 + 8pq^2

= q^2 - 18p + 8

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In the diagram below, we have ST parallel to QR. angle P= 40 degrees, and angle Q= 35 degrees. Find the measure of angles STR in

Drupady [299]

Answer:

$m\angle S = 35^\circ, \ m\angle T = 105^\circ,\ m\angle R = 105^\circ$

Step-by-step explanation:

<u>Similar Triangles</u>

Lines ST and QR are parallel. Thus, angles S and Q are congruent, and angles T and R are congruent.

Considering the triangle PQR, the sum of its internal angles must be 180°:

$m\angle P + m\angle Q + m\angle R = 180^\circ$

Substituting the known values:

$40^\circ + 35^\circ + m\angle R = 180^\circ$

Solving for R:

$m\angle R = 180^\circ - 40^\circ - 35^\circ$

$m\angle R = 105^\circ$

Angles S and Q are congruent, thus

$m\angle S = 35^\circ$

Angles T and R are congruent, thus

$m\angle T = 105^\circ$

Summarizing:

$\mathbf{m\angle S = 35^\circ, \ m\angle T = 105^\circ,\ m\angle R = 105^\circ}$

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3 years ago

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