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3 years ago

Help me on my math please

Mathematics

1 answer:

scoray [572]3 years ago

7 0

1) 9m

2) 1/64

3) 50d^3

4) pq^2 (p-q) (p-q)

= pq^2 ( p^2 - 9p -9p +18)

= pq^4 - 18p^2q^2 + 8pq^2

= q^2 - 18p + 8

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The sum of two numbers is 70. One number is 10 more the twice the other number.

GalinKa [24]

Answer:

20 and 50

Step-by-step explanation:

x + y = 70

y = 2x + 10

Use the substitution method:

y = 70 - x

y = 2x + 10

70 - x = 2x + 10

3x = 60

x = 20

x + y = 70

20 + y = 70

y = 50

x = 20

y = 50

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Find the area of a circle with radius of 6 inches. (Use 3.14 for 1.)

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Answer:

$\pi {r}^{2}$

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SOLVE

Sauron [17]

Answer:

approximately

1623.6

Step-by-step explanation:

16 1/2%=.165 which is approximately equal to 1/6, so we can just multiply the original number by 6.

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3 years ago

What is the area of this circle

antoniya [11.8K]

Answer:

Where is the circle

Step-by-step explanation:

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3 years ago

Find an equation for the line that passes through the points (5.-5) and (-4,-2)

ANEK [815]

Answer:

$\large\boxed{y=-\dfrac{1}{3}x-\dfrac{10}{3}\to x+3y=-10}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (5, -5) and (-4, -2).

Substiute:

$m=\dfrac{-2-(-5)}{-4-5}=\dfrac{-2+5}{-9}=\dfrac{3}{-9}=-\dfrac{1}{3}$

Put the value of the slope and the coordinates of the point (5, -5) to the equation of a line:

$-5=-\dfrac{1}{3}(5)+b$

$-5=-\dfrac{5}{3}+b$ add 5/3 to both sides

$-\dfrac{15}{3}+\dfrac{5}{3}=b\\\\-\dfrac{10}{3}=b\to b=-\dfrac{10}{3}$

Finally we have the equation of a line in the slope-intercept form:

$y=-\dfrac{1}{3}x-\dfrac{10}{3}$

Convert to the standard form (Ax + By = C):

$y=-\dfrac{1}{3}x-\dfrac{10}{3}$ multiply both sides by 3

$3y=-x-10$ add x to both sides

$x+3y=-10$

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3 years ago