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egoroff_w [7]
3 years ago
15

If a total of 13.5 mol of nahco3 and 4.5 mol of c6h8o7 react, how many moles of co2 and na3c6h5o7 will be produced? nahco3(aq) c

6h8o7 (aq) à 3co2(g) 3h2o(s) na3c6h5o7 (aq)
English
1 answer:
sammy [17]3 years ago
6 0
 <span>no reactant is in excess 

moles CO2 = 13.5 
moles H2O = 13.5 
moles Na3C6H5O7 = 13.5 / 3 =4.5

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