If a total of 13.5 mol of nahco3 and 4.5 mol of c6h8o7 react, how many moles of co2 and na3c6h5o7 will be produced? nahco3(aq) c
6h8o7 (aq) à 3co2(g) 3h2o(s) na3c6h5o7 (aq)
1 answer:
<span>no reactant is in excess
moles CO2 = 13.5
moles H2O = 13.5
moles Na3C6H5O7 = 13.5 / 3 =4.5
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