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miss Akunina [59]
4 years ago
15

Select the correct product.

Mathematics
1 answer:
Neporo4naja [7]4 years ago
4 0
We can simplify this by multiplying all the terms together.

2x * x + 2x * 1 + 9 * x + 9 * 1
= 2x^2 + 2x + 9x + 9
= 2x^2 + 11x + 9

Hope this helped!
You might be interested in
Whats a formula for four is no less than the quotient of a number x nd 2.1
Xelga [282]
4≤x/2.1

To Solve

Multiply by 2.1

8.4≤x
5 0
4 years ago
in a right triangle, the 58cm hypotenuse makes a 51 angle with one of the legs. rounded to two decimals places, how long is that
ser-zykov [4K]

Answer:

36.50

To two decimal places

Step-by-step explanation:

The hypothenuse side in a right angle triangle has 58cm. While the angle touching one of its leg is 51°. How long is that leg.

From the right angled triangle, the size of the leg touching the hypothenuse is the adjacent side of the triangle, hence in trigonometry, the cosine rule is used, because it involves the adjacent and the hypotenuse.

Cos 51°=x/58

Let the size of the leg be x

Making x the subject

x=58(Cos51°)

x=36.500058

Correct to two decimal place

x=36.50

3 0
3 years ago
Change to Ax+By=C form. y=-5x+9
Reil [10]

The function is:

y=5x+9

Now to put in the form Ax+By=c we hace to let the number that don't have x ot y in the left side of the equation anthe the rest of the term in the right side of the equation:

-5x+y=9

where:

\begin{gathered} A=-5 \\ B=1 \\ C=9 \end{gathered}

6 0
2 years ago
Answer for these 2 plz? With explanation!
givi [52]

Answer:

Look at the photo

Step-by-step explanation:

I hope I solved it right. Once you get the main concept of it, it's pretty easy.

If you have any questions about the way I solved it, don't hesitate to ask

8 0
3 years ago
At a track meet, Samma finished the 200-meter race in 25.98 seconds. Tom finished the 100-meter race in 12.54 seconds. Which run
ANEK [815]
Time = distance / speed

Samma : 200/25.98 = 7.70 meters per second
Tom : 100 / 12.54 = 7.97 meters per second

so the faster runner is Tom
8 0
3 years ago
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