Question

If you start at vertex A and use the "shortest route" algorithm, what would be the second path to

Answer 1

Answer:

Shortest distance=|AC|/$\sqrt[2]{2}$.

Kindly find the attached for the figure

Step-by-step explanation:

This problem can be addressed using right-angled,

Let have right angle triangle with the shortest distance=hypotenuse;

hypotenuse=|AC|

using pythagoras theorem, we have

|AC|^2=|AB|^2+|BC|^2

Let |AB|=|BC|

|AC|^2=2|AB|^2

|AB|=|AC|/$\sqrt[2]{2}$

Shortest distance=|AC|/$\sqrt[2]{2}$