If you start at vertex A and use the "shortest route" algorithm, what would be the second path to
1 answer:
Answer:
Shortest distance=|AC|/
.
Kindly find the attached for the figure
Step-by-step explanation:
This problem can be addressed using right-angled,
Let have right angle triangle with the shortest distance=hypotenuse;
hypotenuse=|AC|
using pythagoras theorem, we have
|AC|^2=|AB|^2+|BC|^2
Let |AB|=|BC|
|AC|^2=2|AB|^2
|AB|=|AC|/![\sqrt[2]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B2%7D)
Shortest distance=|AC|/![\sqrt[2]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B2%7D)
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